圖像從WP7上傳到Web Api

Question

我在網上看到很少有其他相同的例子，但我不確定為什么它不適合我。

我創建了一個簡單的Windows Phone 7應用程序，它使用PhotoChooserTask。 它使用Web Api將圖像發送到服務器。

這是windows phone項目中的代碼：

   void selectphoto_Completed(object sender, PhotoResult e)
    {
        if (e.TaskResult == TaskResult.OK)
        {
            var image = new Image();
            image.Source = new BitmapImage(new Uri(e.OriginalFileName));

            HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://localhost:59551/api/controllername");
            request.Method = "POST";
            request.ContentType = "multipart/form-data";
//private method to convert bitmap image to byte
            byte[] str = BitmapToByte(image);
            // Getting the request stream.
            request.BeginGetRequestStream
            (result =>
            {
                // Sending the request.
                using (var requestStream = request.EndGetRequestStream(result))
                {
                    using (StreamWriter writer = new StreamWriter(requestStream))
                    {
                        writer.Write(str);
                        writer.Flush();
                    }
                }

                // Getting the response.
                request.BeginGetResponse(responseResult =>
                {
                    var webResponse = request.EndGetResponse(responseResult);
                    using (var responseStream = webResponse.GetResponseStream())
                    {
                        using (var streamReader = new StreamReader(responseStream))
                        {
                            string srresult = streamReader.ReadToEnd();
                        }
                    }
                }, null);
            }, null);

        }

在Web API上，我獲得了POST方法的以下代碼：

public Task<HttpResponseMessage> Post()
    {
        // Check if the request contains multipart/form-data.
        if (!Request.Content.IsMimeMultipartContent())
        {
            throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
        }

        string root = HttpContext.Current.Server.MapPath("~/App_Data");
        var provider = new MultipartFormDataStreamProvider(root);           

        // Read the form data and return an async task.
        var task = Request.Content.ReadAsMultipartAsync(provider).
             ContinueWith<HttpResponseMessage>(t =>
             {
                 if (t.IsFaulted || t.IsCanceled)
                 {
                     Request.CreateErrorResponse(HttpStatusCode.InternalServerError, t.Exception);
                 }

                 // This illustrates how to get the file names.
                 foreach (MultipartFileData file in provider.FileData)
                 {
                     Image img = Image.FromFile(file.LocalFileName);
                     Trace.WriteLine(file.Headers.ContentDisposition.FileName);
                     Trace.WriteLine("Server file path: " + file.LocalFileName);
                 }
                 return Request.CreateResponse(HttpStatusCode.OK);
             });

        return task;            
    }
}

但是我不確定為什么IsMimeMultipartContent總是返回false。 即使我繞過此檢查，App_Data文件夾中也不會保存任何文件。

誰能請幫忙。 謝謝。

EDITED

基於Darrel的響應，我在ApiController中修改了POST方法。 但我仍然沒有得到任何數據。 在服務器上創建一個空白圖像。 這是我的代碼：

 public HttpResponseMessage Post()
 {
 var task = Request.Content.ReadAsStreamAsync();
        task.Wait();
        Stream requestStream = task.Result;


        string root = HttpContext.Current.Server.MapPath("~/App_Data");
        root = System.IO.Path.Combine(root, "xyz.jpg");
        try
        {
            FileStream fs = System.IO.File.OpenWrite(root);
            requestStream.CopyTo(fs);
            fs.Close();
        }
        catch (Exception)
        {
            throw new HttpResponseException(new HttpResponseMessage(HttpStatusCode.InternalServerError));
        }

        HttpResponseMessage response = new HttpResponseMessage();
        response.StatusCode = HttpStatusCode.Created;
        return response;
 }

Answer 1

您沒有發送multipart/form 。 您只是發送一個字節流，即application/octet-stream 。 只需在服務器上使用Request.Content.ReadAsStreamAsync()並將流復制到文件中。