[英]foreach statement echo once if nested foreach is empty?
好的,我有一個foreach語句,在wordpress中跨3個多站點博客搜索關鍵字,如下所示:
<?php
foreach ( $blogs as $blog ):
switch_to_blog($blog['blog_id']);
$search = new WP_Query($query_string);
if ($search->found_posts>0) {
foreach ( $search->posts as $post ) {
echo "POST CONTEN";
}
}elseif ($search->found_posts===0) {
# code...
$notfound = true;
}
endforeach;
if ($notfound) {
# code...
echo "POST NOT FOUND";
}
如果在所有博客中都沒有使用該關鍵字的帖子,則此方法很好,但它回顯了POST NOT FOUND,但是如果博客1中存在一個帖子,而博客2或3中卻沒有,則仍然回顯POST NOT FOUND為什么? 克里斯// * ** * **** 更新 * ** * ** * ** * ** * ** * ** * ** * ** * ** * ** * **** /
<?php
$searchfor = get_search_query(); // Get the search query for display in a headline
$query_string=esc_attr($query_string); // Escaping search queries to eliminate potential MySQL-injections
$blogs = get_blog_list( 0,'all' );
$notfound = true;
foreach ( $blogs as $blog ):
switch_to_blog($blog['blog_id']);
$search = new WP_Query($query_string);
if ($search->found_posts>0) {
$notfound = false;
}
if($notfound){
?>
<div class="post">
<h2><?php _e('Ingen resultater'); ?></h2>
<p><?php _e('Beklager, vi fant ingen innlegg som samsvarer med ditt søk: ' . get_search_query()); ?></p>
</div>
<?php
}else{
foreach ( $search->posts as $post ) {
echo "content";
}
}
endforeach;
?>
您的邏輯是倒退。 您應該以“沒有發現”條件開始,並在發現某些情況時將其更改為false:
$not_found = true;
while ...
if ($search->found_posts != 0) {
$not_found = false;
}
}
if ($not_found) {
echo 'nothing found'; // $not_found is true
} else {
echo 'found something'; // $not_found is false
}
抱歉,格式化。 剛剛在這里復制了代碼。 與您所做的相反,請查看此處的變量$ found。
<?php
$found = false;
foreach ( $blogs as $blog ):
switch_to_blog($blog['blog_id']);
$search = new WP_Query($query_string);
if ($search->found_posts>0) {
foreach ( $search->posts as $post ) {
echo "POST CONTEN";
}
$found = true;
}elseif ($search->found_posts===0) {
# code...
}
endforeach;
if ($found == false) {
# code...
echo "POST NOT FOUND";
}
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