如何在打印語句中組合字符串和整數？

Question

我剛剛開始在大學課程中學習Java。 如果還沒有涵蓋所有陳述，但我認為我可以自己嘗試。 我最后遇到了一些我認為可以解決的語法錯誤，但是現在當我嘗試添加帶有整數的字符串時似乎出現了操作數錯誤。

我班上的問題是向用戶詢問他們的姓名，小時工資率以及他們工作多少小時。 我知道教授很快就會要求我們向用戶詢問他們是否獲得加班費。 如果他們這樣做，請問加班了幾個小時。 然后計算總付款額，其中任何加班費均為正常時薪的1.5倍。

但是我在最后3個打印語句中遇到錯誤，我認為這是因為我試圖將字符串和整數組合在一起。 我該如何解決？

package javaapplication2;

import java.util.Scanner;

public class JavaApplication2 {

    public static void main(String [] args) {
        Scanner input = new Scanner(System.in);
        String name;
        double payRate;
        int hours;
        Boolean OTyn;
        int OTy;

        System.out.println("What is your name?");
        name = input.nextLine();
        System.out.println("What is your hourly rate of pay?");
        payRate = input.nextDouble();
        System.out.println("How any hours have you worked?");
        hours = input.nextInt();
        System.out.println("Your boss pays overtime. Answer with true or false.");
        OTyn = input.nextBoolean();
        if (OTyn == true) 
            System.out.println("After how many hours are you paid for overtime?");
            OTy = input.nextInt();
            if (hours > OTy)
                System.out.println("Your weekly pay is " + ((40 * payRate) + (hours - OTy)(payRate * 1.5)));
            else
                System.out.println("Your weekly pay is " + payRate * hours);
        else
            System.out.println("Your weekly pay is " + payRate * hours);
    }
}

Answer 1

我認為您在ifs上缺少{}

if (OTyn == true) { //here
    System.out.println("After how many hours are you paid for overtime?");
    OTy = input.nextInt();
    if (hours > OTy){ // Here doesn need because it is just one line after the if
        System.out.println("Your weekly pay is " + 
                 ((40*payRate) + (hours - OTy)(payRate*1.5))); 
     // (hours - OTy)(payRate*1.5) you are missing an operator between this expressions

    }else{
        System.out.println("Your weekly pay is " + payRate*hours);
    }
} else { //here
    System.out.println("Your weekly pay is " + payRate*hours);
} //and here

另外，對於僅后一行的IF語句，您不需要{}因為：

if ( something )
   System.out.println("Something is true");
else
   System.out.println("Something is false");

Answer 2

您缺少一組括號和一個星號，如下所示。

if (OTyn == true) { // <-- This brace to open.
  System.out
      .println("After how many hours are you paid for overtime?");
  OTy = input.nextInt();
  if (hours > OTy)
    System.out.println("Your weekly pay is "
        + ((40 * payRate) + (hours - OTy)
            * (payRate * 1.5))); // <-- at the start of this line.
  else
    System.out.println("Your weekly pay is "
        + payRate * hours);
} else // <-- That brace to close.
  System.out.println("Your weekly pay is "
      + payRate * hours);

Answer 3

import java.util.Scanner;

public class JavaApplication2 
{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String name;
double payRate;
int hours;
Boolean OTyn;
int OTy;

System.out.println("What is your name?");
name = input.nextLine();
System.out.println("What is your hourly rate of pay?");
payRate = input.nextDouble();
System.out.println("How any hours have you worked?");
hours = input.nextInt();
System.out.println("Your boss pays overtime. Answer with true or false.");
OTyn = input.nextBoolean();
if (OTyn == true){
    System.out.println("After how many hours are you paid for overtime?");
    OTy = input.nextInt();
    if (hours > OTy){
        System.out.println("Your weekly pay is " + ((40*payRate) + (hours - OTy)*(payRate*1.5)));
    }
    else{
        System.out.println("Your weekly pay is " + payRate*hours);
    }
}
else {
    System.out.println("Your weekly pay is " + payRate*hours);
}
}    
}

試試這個，不僅您缺少括號，而且此行也有問題

System.out.println("Your weekly pay is " + ((40*payRate) + (hours - OTy)(payRate*1.5)));

您需要在(hours - OTy)和(payRate*1.5)之間(payRate*1.5)以(hours - OTy)*(payRate*1.5)否則字符串連接將不起作用