SQL：從最早到最新的約會開始，對每條記錄進行計數

Question

我有一個如下表，其中我需要對每個約會進行計數並按ID和Type進行分組，然后按最舊的約會進行排序，並給它一個數字並加起來。

我正在使用MS SQL服務器管理工​​作室。

Select ID, Date, Type
From Appointment
Where Type='Post-op'

之前

ID  | Date          | Type
123 | 2013-01-01    | Post-op
123 | 2013-01-21    | Post-op
123 | 2013-02-28    | Post-op
123 | 2013-05-16    | Post-op
124 | 2013-01-21    | Post-op
124 | 2013-02-12    | Post-op

后

ID  | Date          | Type      | Count
123 | 2013-01-01    | Post-op   | 1
123 | 2013-01-21    | Post-op   | 2
123 | 2013-02-28    | Post-op   | 3
123 | 2013-05-16    | Post-op   | 4
124 | 2013-01-21    | Post-op   | 1
124 | 2013-02-12    | Post-op   | 2

謝謝

Answer 1

在SELECT中使用窗口功能

SELECT id
      ,[date]
      ,type
      ,ROW_NUMBER() OVER (PARTITION BY ID ORDER BY [date] ) AS seq
FROM  Appointment
WHERE Type = 'Post-op'

SqlFiddle： http ://sqlfiddle.com/#!3/f3a4f/1

Answer 2

似乎您在ROW_NUMBER之后

;with TempData as (Select ID  ,Date,Type DataCount =ROW_NUMBER()
                    over(PARTITION By Id Order By Date)
                    From Appointment
                    Where Type='Post-op')

Select * from TempData