[英]Android Class with sub-class AsyncTask wait for the postExecute before returning the value
目前,我正在為我的項目做某事,其中我創建了一個單獨的類,該類僅處理Asynctask並獲取我傳遞的Web服務的值,並且該類應以字符串形式返回JSON響應。 現在我已經使用taskName.execute().get();
其中它會等待任務完成,但是問題在於它還在顯示屏幕布局之前正在等待任務完成。 使我的progressDialog無用,並導致切換屏幕的延遲。 現在是我的代碼:
對於帶有AsyncTask的類:
public class UtilGetResponse {
Context context;
Map hash_values = new HashMap();
int DialogType;
String response;
/*
PLAN FOR DialogTypes:
* 0 - Standard Please wait dialog
* 1 - Progress dialog
* 2 - Camera upload dialog
* */
InputStream is = null;
StringBuilder string_builder = null;
public UtilGetResponse(Map values, Context baseContext, int type){
/*initialize class and pass the hash values for parameters*/
context = baseContext;
hash_values.putAll(values);
DialogType = type;
}
public String startTask(){
//TODO CASE WHEN BASED ON THE DIALOG TYPE SPECIFIED
Utilities util = new Utilities();
if(util.isOnline(context)){
try {
new UploaderTaskStandard().execute().get();
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
}
}
return response; //THE RESPONSE ONLY SHOW ONCE THE WHOLE TASK IS COMPLETED
}
public class UploaderTaskStandard extends AsyncTask<Map, Void, Void> {
ProgressDialog simpleDialog;
@Override
protected void onPreExecute() {
/*Do something before the async task starts*/
simpleDialog = new ProgressDialog(context);
simpleDialog.setMessage("Please wait");
simpleDialog.show();
}
@Override
protected Void doInBackground(Map... maps) {
uploadData();
return null;
}
protected void onPostExecute(Void v) {
/*Do something after the task is complete*/
simpleDialog.dismiss();
}
}
private void uploadData() {
response = "null";
String url = hash_values.get("url").toString().replace(" ", "%20"); //get the URL replacing the space with %20
//If the user is trying to upload a file use this part
try {
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost(url);
MultipartEntity mpEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);
/*This will convert the hashMap sent into individual part per key per value*/
Set set = hash_values.entrySet();
Iterator iterator = set.iterator();
/*do a loop passing all the data on a string*/
while(iterator.hasNext()) {
Map.Entry mapEntry = (Map.Entry)iterator.next();
String keyword = String.valueOf(mapEntry.getKey());
String value = String.valueOf(mapEntry.getValue());
/*this will check if the passed data is a URL, file or a simple value*/
if(!keyword.equals("url")){
if(value.matches("(.*)/(.*)")){
File file = new File(value);
Log.v("Does this exists?",String.valueOf(file.exists()));
if(file.exists()){
FileBody upload_file;
upload_file = new FileBody(file);
/*not url but file*/
mpEntity.addPart(keyword, upload_file);
}else{
/*not url and not file*/
mpEntity.addPart(keyword, new StringBody(value));
}
}else{
/*not URL and not file*/
mpEntity.addPart(keyword, new StringBody(value));
}
}
}
post.setEntity(mpEntity);
HttpResponse response = client.execute(post);
HttpEntity resEntity = response.getEntity();
is = resEntity.getContent();
} catch (Exception e) {
e.printStackTrace();
response = "null";
}
/*convert JSON to string*/
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
string_builder = new StringBuilder();
String line = "0";
while ((line = reader.readLine()) != null) {
string_builder.append(line + "\n");
}
is.close();
response = string_builder.toString();
}catch(Exception e){
e.printStackTrace();
}
}
}
並稱之為:
Map hash_values = new HashMap();
try{
HashMap params = new HashMap<String,String>();
params.put("param1", "YOUR_PARAM");
params.put("url", "YOUR_WEBSERVICE_URL");
//pass parameters
hash_values.putAll(params);
//start async task
UtilGetResponse util = new UtilGetResponse(hash_values, getActivity(), 0);
String result = util.startTask();
Log.v("The result string",result);
}catch (Exception e){
e.printStackTrace();
e.getCause();
Toast.makeText(getActivity(), "Oops problem", Toast.LENGTH_SHORT).show();
}
有沒有辦法讓我正確地執行此操作,而無需真正等待整個任務完成才移到下一個屏幕? 我正在考慮使用處理程序,但是無論如何我都不是很熟悉。
您的問題在於此用法
new UploaderTaskStandard().execute().get();
盡管您使用的是AsynTask,但仍使系統等到結果超出您的要求時,您需要的是一種傳遞機制,一旦結果准備好,它將通知您。 您可以采用兩種方法之一。
change to this, and implement one of below mechanism.
new UploaderTaskStandard().execute();
onResultReady
之類的方法的startTask
,並將實現上述接口的類的對象傳遞給方法startTask
,並將結果通過接口機制從AsyncTask onPostExecute
回onPostExecute
。 通過接口進行操作非常容易,這樣您的代碼將獨立於您的網絡邏輯,下面的示例代碼
// Observer listener interface design
interface ResultListener{
// You can overload this method with data type you want to return
public void onResultReceived();
// Use them in a proper way for sending error message back to your program
public void onTaskCancelled();
public void onError();
}
// This will be your new method signature
public String startTask(ResultListener listener){
// Call it liske this, passing listener reference
new UploaderTaskStandard().execute(listener);
}
// This is your AsyncTask model
public class UploaderTaskStandard extends AsyncTask<ResultListener, Void, Void> {
ResultListener listener;
@Override
protected Void doInBackground(ResultListener... maps) {
this.listener = maps[0];
uploadData();
return null;
}
protected void onPostExecute(Void v) {
/*Do something after the task is complete*/
simpleDialog.dismiss();
// Notify back to calling program
listener.onResultReceived();
}
}
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