[英]Challenging LEFT OUTER JOIN query grouping by MAX
我有以下兩個表:
BillingMatrixDefinition
- id
- amount
BillingMatrix
- definition (FK to table above)
- service_id (FK)
- provider_id (FK)
- amount (Decimal)
我需要獲取具有我指定的service_id
和provider_id
所有BillingMatrixDefinitions。 這是我當前擁有的SQL查詢:
select def.id, service_id, provider_id,
(case when matrix.amount is not null then matrix.amount else def.amount end) amount
from billing_billingdefinition def
left outer join billing_billingmatrix matrix
on matrix.definition_id=def.id
where (service_id = 25 or service_id is null)
and (provider_id = 24 or provider_id is null)
這給了我以下結果:
id service_id provider_id amount
1 25 24 200.00
1 NULL 24 300.00
2 NULL 24 800.00
3 NULL NULL 750.00
5 NULL NULL 450.00
6 NULL NULL 750.00
但是,我需要得到每個ID的結算量,所以我只能得到一個項目/金額為每個id
。 在這種情況下,我想獲取service_id=24
的項目,如果不存在,請在service_id=NULL
。
正確的查詢應該給我以下結果:
id service_id provider_id amount
1 25 24 200.00
2 NULL 24 800.00
3 NULL NULL 750.00
5 NULL NULL 450.00
6 NULL NULL 750.00
請注意,現在沒有1的重復條目,我使用已輸入service_id的行項目(如果存在,則使用該項目,否則使用NULL)。 什么是正確的查詢來做到這一點?
另一種方式:
SELECT
def.id AS id,
COALESCE(matrix.service_id, matrix2.service_id) AS service_id,
COALESCE(matrix.provider_id, matrix2.provider_id) AS provider_id,
COALESCE(matrix.amount, matrix2.amount, def.amount) AS amount
FROM
billing_billingdefinition AS def
LEFT JOIN
billing_billingmatrix AS matrix
ON matrix.definition_id = def.id
AND matrix.service_id = 25
AND matrix.provider_id = 24
LEFT JOIN
billing_billingmatrix AS matrix2
ON matrix2.definition_id = def.id
AND matrix2.service_id IS NULL
AND matrix2.provider_id = 24 ;
嘗試以下方法(利用臨時表):
CREATE TEMPORARY TABLE Results
select def.id, service_id, provider_id,
(case when matrix.amount is not null then matrix.amount else def.amount end) amount
from billing_billingdefinition def
left outer join billing_billingmatrix matrix
on matrix.definition_id=def.id
where (service_id = 25 or service_id is null)
and (provider_id = 24 or provider_id is null);
SELECT *
FROM Results r1
WHERE IFNULL(r1.service_id, 0) =
( SELECT MAX(IFNULL(r2.service_id, 0))
FROM Results r2
WHERE r2.id = r1.id
);
SQL Fiddle僅用於第二部分(使用已經創建的Results
表)
您需要使用max()
來匯總金額max()
當然還要添加group-by子句),以便在存在一個非null值的情況下獲得該值:
select
def.id, service_id, provider_id,
max(case when matrix.amount is not null then matrix.amount else def.amount end) amount
from billing_billingdefinition def
left outer join billing_billingmatrix matrix
on matrix.definition_id=def.id
where (service_id = 25 or service_id is null)
and (provider_id = 24 or provider_id is null)
group by def.id, service_id, provider_id
這樣的事情也可能起作用。
select def.id, service_id, provider_id, IFNULL(matrix.amount,def.amount) amount
from billing_billingdefinition def
left outer join (select definition_id, max(service_id) as maxsid from billing_billingmatrix matrix group by definition_id) as t1
on def.id = t1.definition_id
left outer join billing_billingmatrix matrix
on matrix.definition_id=def.id and maxsid <=> service_id
嘗試這個:
SELECT BMD.id, BM.service_id, BM.provider_id, IFNULL(BM.amount, BMD.amount) AS amount
FROM BillingMatrixDefinition BMD
LEFT JOIN BillingMatrix BM ON BMD.id = BM.definition_id AND (BM.service_id = 25 OR BM.provider_id = 24)
GROUP BY BMD.id;
我相信PM 771的答案在這里也適用,但是我決定在OUTER JOIN
表中使用子選擇,以在加入之前對結果進行預過濾。
這是為此工作的最終SQL:
SELECT *,
(CASE WHEN matrix.amount IS NOT NULL THEN matrix.amount ELSE def.amount END) calculated_amount,
FROM billing_billingdefinition def
LEFT OUTER JOIN
(SELECT t.* FROM (
select * from billing_billingmatrix
where (provider_id=25
or provider_id is null)
and (service_id=24 or service_id is null)
ORDER BY service_id DESC
) t GROUP BY t.definition_id) matrix
ON matrix.definition_id=def.id
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