[英]C# Extend Generic Class in Method call
我正在嘗試編寫一個傳遞泛型參數的方法,該參數將使用泛型參數擴展一個類,但我不想將第二個泛型參數傳遞給該方法。 有沒有辦法在不傳遞兩個通用參數的情況下實現我想要做的事情?
// this base doesn't work because it expects a BaseReportViewModel<D>
// I don't want to have to pass in two generic arguments from the child controller
// this is what I don't want to do: this.ReportView<Report1ViewModel, Report1Data>(viewModel);
// I want to ONLY have to pass in a single generic argument.
public class BaseController {
// the below line won't compile because it expects a generic type to be passed to BaseReportViewModel<>
public ActionResult ReportView<T>(T viewModel) where T : BaseReportViewModel {
viewModel.ReportGroup = this.ReportGroup;
viewModel.ReportTitle = this.ReportTitle;
return this.View(viewModel);
}
}
public class ChildController {
var viewModel = new Report1ViewModel();
viewModel.Data = new Report1Data();
return this.ReportView<Report1ViewModel>(viewModel);
}
public class BaseReportViewModel<T> : BaseViewModel where T : ReportBaseData {
public string ReportGroup { get; set; }
public string ReportTitle { get; set; }
public T Data { get; set; }
}
public class Report1ViewModel : BaseReportViewModel<Report1Data> {
}
public class Report1Data : BaseReportData {
}
我想你想要這樣的東西
public ActionResult ReportView<T>(BaseReportViewModel<T> viewModel)
where T : ReportBaseData
旁注:你也不需要在this.ReportView<Report1ViewModel>(viewModel);
傳遞類型this.ReportView<Report1ViewModel>(viewModel);
調用,只需ReportView(viewModel);
應該足夠,因為類型應該從參數派生。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.