[英]Query a specific value with Pivot Table mySQL
我已經在整個互聯網上進行了搜索,但是沒有運氣找到問題的答案。 我希望這還沒有專門發布,但是如果您能指出我可以找到答案的地方,我將不勝感激。
我能夠獲取以下表格數據:
id lead_id form_id field_number value
1 1 1 1 Hosker
2 1 1 7 b**********@yahoo.com
3 1 1 6 Hyundai Tournament of Champions
4 1 1 3 Adam Scott
5 1 1 4 Harris English
6 1 1 5 2014-01-02 23:59:47
7 1 1 8 5b409692-e9ed-486e-8d77-7d734f1e023d
並使用以下查詢字符串獲取以下結果:
SELECT id, lead_id, form_id,
MAX(case when field_number = 1 then value end) username,
MAX(case when field_number = 7 then value end) email,
MAX(case when field_number = 6 then value end) tournament_name,
MAX(case when field_number = 3 then value end) primary_golfer,
MAX(case when field_number = 4 then value end) backup_golfer,
MAX(case when field_number = 5 then value end) date,
MAX(case when field_number = 8 then value end) tournament_id
FROM `wp_rg_lead_detail` GROUP BY lead_id
id lead_id form_id field_number value value value value value value value
1 1 1 1 Hosker b**********@yahoo.com Hyundai Tournament of Champions Adam Scott Harris English 2014-01-02 23:59:47 5b409692-e9ed-486e-8d77-7d734f1e023d
我只希望該查詢字符串僅在race_id列的值等於特定值時才提取相關數據。 我該怎么辦?
如果我了解您的要求,請嘗試:
SELECT * FROM TABLE_NAME
WHERE tournament_id = specific_value;
試試這個查詢。 我認為您可以使用HAVING
子句。
SELECT id, lead_id, form_id,
MAX(case when field_number = 1 then value end) username,
MAX(case when field_number = 7 then value end) email,
MAX(case when field_number = 6 then value end) tournament_name,
MAX(case when field_number = 3 then value end) primary_golfer,
MAX(case when field_number = 4 then value end) backup_golfer,
MAX(case when field_number = 5 then value end) date,
MAX(case when field_number = 8 then value end) tournament_id
FROM `wp_rg_lead_detail` GROUP BY lead_id
HAVING tournament_id = '5b409692-e9ed-486e-8d77-7d734f1e023d'
sqlFiddle在sqlFiddle中,我有2個不同的tour_id的示例數據,並且應用了HAVING
子句,以便僅返回該tour_id的值,您可以嘗試刪除HAVING並看到它返回2行。
由於您同時選擇了id和form_id,因此Group By不是標准的。 我建議您刪除id或使用MIN(id)或MAX(id)和GROUP BY lead_id,form_id
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