[英]Counting number of words between punctuation characters in Python
我想使用Python來計算文本輸入塊中某些標點符號之間出現的單詞數。 例如,對到目前為止編寫的所有內容的這種分析可以表示為:
[23,2,14]
...因為第一個句子除了結尾的句點外沒有其他標點符號,所以有23個單詞,接下來出現的“例如”短語有兩個單詞,其余以冒號結尾的單詞有14個單詞。
這樣做可能並不難,但是(與似乎沒有Pythonic的“不要重新發明輪子”哲學相伴隨)是否已經有特別適合該任務的內容?
punctuation_i_care_about="?.!"
split_by_punc = re.split("[%s]"%punctuation_i_care_about, some_big_block_of_text)
words_by_puct = [len(x.split()) for x in split_by_punc]
Joran擊敗了我,但我將添加自己的方法:
from string import punctuation
import re
s = 'I want to use Python to count the numbers of words that occur between certain punctuation characters in a block of text input. For example, such an analysis of everything written up to this point might be represented as'
gen = (x.split() for x in re.split('[' + punctuation + ']',s))
list(map(len,gen))
Out[32]: [23, 2, 14]
(我愛map
)
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