[英]Counting number of words between punctuation characters in Python
我想使用Python来计算文本输入块中某些标点符号之间出现的单词数。 例如,对到目前为止编写的所有内容的这种分析可以表示为:
[23,2,14]
...因为第一个句子除了结尾的句点外没有其他标点符号,所以有23个单词,接下来出现的“例如”短语有两个单词,其余以冒号结尾的单词有14个单词。
这样做可能并不难,但是(与似乎没有Pythonic的“不要重新发明轮子”哲学相伴随)是否已经有特别适合该任务的内容?
punctuation_i_care_about="?.!"
split_by_punc = re.split("[%s]"%punctuation_i_care_about, some_big_block_of_text)
words_by_puct = [len(x.split()) for x in split_by_punc]
Joran击败了我,但我将添加自己的方法:
from string import punctuation
import re
s = 'I want to use Python to count the numbers of words that occur between certain punctuation characters in a block of text input. For example, such an analysis of everything written up to this point might be represented as'
gen = (x.split() for x in re.split('[' + punctuation + ']',s))
list(map(len,gen))
Out[32]: [23, 2, 14]
(我爱map
)
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