向量的索引/最大值/最小值 <double> C ++

Question

我希望能夠找出向量中的最高和最低元素，並找出該高/低數字當前在哪個位置/索引。 例如，

vector<double> x;
std::cout << "Enter in #s: ";
double numbers;
std::getline(std::cin, numbers);
x.push_back(numbers);

假設用戶輸入了4.3 1.0 2.99 43.5

我想要結果說

The highest number is 43.5 at position 4
The lowest number is 1.0 at position 2

我想知道是否有沒有辦法使用min_element / max_element函數來實現此代碼而無需使用for循環？

我想使用類似：

for (int i=0;i < x.size();i++)
    if ( //the number is less than ) {
        std::cout << "The lowest number is...... at position .....";
    if ( //the number is greather than ) {
        std::cout << "The highest number is......at position......";

Answer 1

將每個數字與迄今為止找到的最佳最大值/最小值進行比較。
如果較大/較小，則用最大值/最小值替換並記下索引

您將需要一個max和min變量以及兩個索引-如果將max和min設置為，請謹慎設置初始值

Answer 2

為此，您需要存儲最高和最低元素的索引，並將它們與每次迭代的當前元素進行比較。

// Note: the below code assumes that the container (vector) is not empty
//    you SHOULD check if the vector contains some elements before executing the code below

int hi, lo;    // These are indices pointing to the highest and lowest elements
hi = lo = 0;   // Set hi and lo to the first element's index

// Then compare the elements indexed by hi and lo with the rest of the elements
for (int i = 1;i < x.size();i++) {
    if(x[i] < x[lo]) {
        // The element indexed by i is less than the element indexed by lo
        //    so set the index of the current lowest element to i
        lo = i;
    }
    // Below, else if is used and not if because the conditions cannot be both true
    else if(x[i] > x[hi]) {
        // Same logic as the above, only for the highest element
        hi = i;
    }
}

// Note: the position indicated by the output below will be 0-based
std::cout << "The lowest number is " << x[lo] << " at position " << lo << ".\n";
std::cout << "The highest number is " << x[hi] << " at position " << hi << ".\n";

現場演示

Answer 3

    size_t iMax=0,iMin=0;
    for(size_t i=1; i<x.size(); ++i)
    {
            if(x[iMax] < x[i])
                    iMax=i;
            if(x[iMin] > x[i])
                    iMin=i;
    }
    //iMax is index of the biggest num in the array