mySQLi查詢未提供正確的信息

Question

我做了這個腳本：

$username = $_POST["username"];
$password = sha1($_POST["password"]);
$checkuser_query = mysqli_query($con,"SELECT * FROM users WHERE username='$username' AND password='$password'");
$checkuser = mysqli_num_rows($checkuser_query);
$checkactive_query = mysqli_query($con,"SELECT * FROM users WHERE username='$username' AND verified='0'");
$checkactive = mysqli_num_rows($checkactive_query);
$checkbanned_query = mysqli_query($con,"SELECT * FROM users WHERE username='$username' AND closed='1'");
$checkbanned = mysqli_num_rows($checkactive_query);
if(empty($_POST["username"]) || empty($_POST["password"])) {
    header("Location: http://empirebattles.co.uk/Login?alert=nofilled");
}
elseif($checkuser<= 0) {
    header("location: http://empirebattles.co.uk/Login?alert=loginfailed");
}
elseif($checkactive==1) {
    header("location: http://empirebattles.co.uk/Login?alert=unverified");
}
elseif($checkbanned==1) {
    header("location: http://empirebattles.co.uk/Login?alert=banned");
}       
else {
    header("Location: http://empirebattles.co.uk/Home");
    setcookie("EmpireBattles",$username,time() + (10 * 365 * 24 * 60 * 60),"/");
    mysqli_query($con,"UPDATE users SET online = '1' WHERE username = '$username'");
}

並且，它起作用。 直到禁止您重定向它為止。 即使您被禁止，它也會跳過它。

我看了一遍，用谷歌搜索，甚至問我的老師，沒有人知道有什么問題。

湯姆，請看看。

Answer 1

嘗試更改此行：

  $checkbanned = mysqli_num_rows($checkactive_query);

至

  $checkbanned = mysqli_num_rows($checkbanned_query );