[英]mysqli_query and mysqli_fetch_assoc giving errors
我一直在嘗試找到我訪問index.php文件時發現的mysql錯誤消息的解決方法,代碼如下:
Warning: mysqli_query() expects parameter 1 to be mysqli, resource given in /Applications/XAMPP/xamppfiles/htdocs/cms/includes/navigation.php on line 24
Warning: mysqli_fetch_assoc() expects parameter 1 to be mysqli_result, null given in /Applications/XAMPP/xamppfiles/htdocs/cms/includes/navigation.php on line 26
對於我的生活,我無法弄清楚我在這里做錯了什么,因為它在我使用靜態鏈接時起作用,但在測試動態鏈接時,它只是一個問題。
下面是我用於navigation.php文件的代碼,該文件用盡了包含文件夾:
<nav class="navbar navbar-inverse navbar-fixed-top" role="navigation">
<div class="container">
<!-- Brand and toggle get grouped for better mobile display -->
<div class="navbar-header">
<button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#bs-example-navbar-collapse-1">
<span class="sr-only">Toggle navigation</span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
<span class="icon-bar"></span>
</button>
<a class="navbar-brand" href="#">Start Bootstrap</a>
</div>
<!-- Collect the nav links, forms, and other content for toggling -->
<div class="collapse navbar-collapse" id="bs-example-navbar-collapse-1">
<ul class="nav navbar-nav">
<?php
$query = "SELECT * FROM categories";
$please_work = mysqli_query($connection, $query);
while($row = mysqli_fetch_assoc($please_work)){
$cat_title = $row['cat_title'];
echo "<li><a href='#'>{$cat_title}</a></li>";
}
?>
</ul>
</div>
<!-- /.navbar-collapse -->
</div>
<!-- /.container -->
</nav>
當然我的db.php文件也位於我的包含文件夾中:
<?php
$db['db_host'] = "localhost";
$db['db_user'] = "root";
$db['db_pass'] = "";
$db['db_name'] = "cms";
foreach($db as $key => $value){
define(strtoupper($key), $value);
}
$connection = mysql_connect(DB_HOST, DB_USER, DB_PASS, DB_NAME);
if($connection){
echo "We are connected";
}
?>
我不太需要發布我的index.php,因為我知道錯誤不是來自那里,因為靜態內容在使用時工作,這意味着include函數正在工作。
有人可以讓我免於長期頭痛嗎?
謝謝,
CB
你正在混合mysql_*
和mysqli_*
函數。 你應該總是使用mysqli_*
。
所以,你需要改變這個:
$connection = mysql_connect(DB_HOST, DB_USER, DB_PASS, DB_NAME);
對此:
$connection = mysqli_connect(DB_HOST, DB_USER, DB_PASS, DB_NAME);
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