如何為以下命令行形成PHP curl請求？

Question

有人可以幫助我在PHP中形成此commndline請求嗎？

$ curl -u [USER:PASSWORD] https://subs.pinpayments.com/api/v4/meresheep/subscribers/7388.xml

我嘗試了以下操作，並且只返回了“ false” ...

 // Query the user to pin payments for the details...
 $curl_url = "https://subs.pinpayments.com/api/v4/xyz-site/subscribers/32.xml";

 //open connection
 $ch = curl_init();

 //set the url, number of POST vars, POST data
 curl_setopt($ch, CURLOPT_URL, $url);
 curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
 curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
 curl_setopt($ch, CURLOPT_HTTPHEADER, array('Authorization: -u [USER:PASSWORD]'));

 //execute post
 $result = curl_exec($ch);
 curl_close($ch);

Answer 1

您需要更改CURLOPT_HTTPHEADER行：

curl_setopt($data, CURLOPT_HTTPHEADER, array(
    'Authorization: Basic ' . base64_encode('username:password')
));