如何編寫用於以下CURL命令的php代碼？

Question

如何編寫用於以下CURL命令的php代碼？

curl -H“授權：bearer oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L” https://api.url.com/v1/market/total-items.json

Answer 1

我想你需要這樣的東西：

<?php 

        $url = "https://api.url.com/v1/market/total-items.json"; 
        $page = "/v1/market/total-items.json";
        $headers = array( 
            "POST ".$page." HTTP/1.0", 
            "Authorization: Bearer oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L" 
        ); 

        $ch = curl_init(); 
        curl_setopt($ch, CURLOPT_URL,$url); 
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
        curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); 

        $data = curl_exec($ch); 

Answer 2

您可以從github 分支為此生成cURL命令的PHP代碼。 這是為您的請求生成的：

<?php
$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, "https://api.url.com/v1/market/total-items.json");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "GET");


$headers = array();
$headers[] = "Authorization: Bearer oVi4yPxk1bJ64Y2qOsLJ2D2ZlC3FpK4L";
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

$result = curl_exec($ch);
if (curl_errno($ch)) {
    echo 'Error:' . curl_error($ch);
}
curl_close ($ch);