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[英]SQLAlchemy: Multiple foreign keys to same table with compound primary key
[英]SQLAlchemy multiple foreign keys in one mapped class to the same primary key
我正在嘗試建立一個PostgreSQL表,該表具有兩個指向另一個表中相同主鍵的外鍵。
運行腳本時出現錯誤
sqlalchemy.exc.AmbiguousForeignKeysError:無法確定關系Company.stakeholder的父/子表之間的聯接條件-有多個鏈接表的外鍵路徑。 指定“ foreign_keys”參數,提供這些列的列表,這些列應被視為包含對父表的外鍵引用。
那是SQLAlchemy文檔中的確切錯誤,但是當我復制他們作為解決方案提供的內容時,該錯誤不會消失。 我可能做錯了什么?
#The business case here is that a company can be a stakeholder in another company.
class Company(Base):
__tablename__ = 'company'
id = Column(Integer, primary_key=True)
name = Column(String(50), nullable=False)
class Stakeholder(Base):
__tablename__ = 'stakeholder'
id = Column(Integer, primary_key=True)
company_id = Column(Integer, ForeignKey('company.id'), nullable=False)
stakeholder_id = Column(Integer, ForeignKey('company.id'), nullable=False)
company = relationship("Company", foreign_keys='company_id')
stakeholder = relationship("Company", foreign_keys='stakeholder_id')
我在這里看到了類似的問題,但一些問題的答案推薦一個使用primaryjoin
但在文檔中就指出,你不需要primaryjoin
在這種情況下。
試圖從foreign_keys中刪除引號並將它們制成列表。 來自有關Relationship Configuration: Handling Multiple Join Paths
官方文檔Relationship Configuration: Handling Multiple Join Paths
在版本0.8中進行了更改:
relationship()
可以僅基於foreign_keys
參數解決外鍵目標之間的歧義; 在這種情況下,不再需要primaryjoin
參數。
下面的自包含代碼適用於sqlalchemy>=0.9
:
from sqlalchemy import create_engine, Column, Integer, String, ForeignKey
from sqlalchemy.orm import relationship, scoped_session, sessionmaker
from sqlalchemy.ext.declarative import declarative_base
engine = create_engine(u'sqlite:///:memory:', echo=True)
session = scoped_session(sessionmaker(bind=engine))
Base = declarative_base()
#The business case here is that a company can be a stakeholder in another company.
class Company(Base):
__tablename__ = 'company'
id = Column(Integer, primary_key=True)
name = Column(String(50), nullable=False)
class Stakeholder(Base):
__tablename__ = 'stakeholder'
id = Column(Integer, primary_key=True)
company_id = Column(Integer, ForeignKey('company.id'), nullable=False)
stakeholder_id = Column(Integer, ForeignKey('company.id'), nullable=False)
company = relationship("Company", foreign_keys=[company_id])
stakeholder = relationship("Company", foreign_keys=[stakeholder_id])
Base.metadata.create_all(engine)
# simple query test
q1 = session.query(Company).all()
q2 = session.query(Stakeholder).all()
最新文檔:
文檔中foreign_keys=
的形式會產生NameError,不確定在尚未創建類時預期如何工作。 通過一些黑客,我得以成功實現了這一點:
company_id = Column(Integer, ForeignKey('company.id'), nullable=False)
company = relationship("Company", foreign_keys='Stakeholder.company_id')
stakeholder_id = Column(Integer, ForeignKey('company.id'), nullable=False)
stakeholder = relationship("Company",
foreign_keys='Stakeholder.stakeholder_id')
換一種說法:
… foreign_keys='CurrentClass.thing_id')
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