[英]Multiple foreign keys in one to many relationship - SqlAlchemy
我是 SQL Alchemy 的新手,我需要幫助來實現以下關系:
我有兩個表Trends和ClosestTrends ,我想聲明兩個一對多關系:
在 SQL 中,它將是:
ALTER TABLE "closest_trends" ADD FOREIGN KEY ("id_trend_ref") REFERENCES "trends" ("id") ON DELETE CASCADE;
ALTER TABLE "closest_trends" ADD FOREIGN KEY ("id_trend_close") REFERENCES "trends" ("id") ON DELETE CASCADE;
我嘗試了以下實現:
class Trends(Base):
__tablename__ = "trends"
__table_args__ = (
UniqueConstraint(
"name", "id_region", "language_iso", name="name_id_region_language"
),
)
id = Column(Integer, primary_key=True, index=True, unique=True)
.
.
.
closest_trends = relationship("ClosestTrends", backref="Trends")
def __str__(self):
return "Trends"
class ClosestTrends(Base):
__tablename__ = "closest_trends"
__table_args__ = (
UniqueConstraint(
"id_trend_ref", "id_trend_close", name="id_trend_ref_id_trend_close"
),
)
id = Column(Integer, primary_key=True, index=True, unique=True)
.
.
.
id_trend_ref = Column(
Integer, ForeignKey("trends.id", ondelete="CASCADE"), nullable=False
)
id_trend_close = Column(
Integer, ForeignKey("trends.id", ondelete="CASCADE"), nullable=False
)
def __str__(self):
return "ClosestTrends"
我不工作,我收到以下錯誤:
sqlalchemy.exc.AmbiguousForeignKeysError:無法確定關系 Trends.closest_trends 上父/子表之間的連接條件 - 有多個外鍵路徑鏈接表。 指定“foreign_keys”參數,提供應被視為包含對父表的外鍵引用的列的列表。
有誰知道如何解決這個問題?
非常感謝
您的解決方案寫在官方網站上。
https://docs.sqlalchemy.org/en/13/orm/join_conditions.html#handling-multiple-join-paths
根據官方網站,我是這樣實現的。
class Trends(Base):
__tablename__ = "trends"
__table_args__ = (
UniqueConstraint(
"name", "id_region", "language_iso", name="name_id_region_language"
),
)
id = Column(Integer, primary_key=True, index=True, unique=True)
.
.
.
# closest_trends = relationship("ClosestTrends", backref="Trends")
def __str__(self):
return "Trends"
class ClosestTrends(Base):
__tablename__ = "closest_trends"
__table_args__ = (
UniqueConstraint(
"id_trend_ref", "id_trend_close", name="id_trend_ref_id_trend_close"
),
)
id = Column(Integer, primary_key=True, index=True, unique=True)
.
.
.
id_trend_ref = Column(
Integer, ForeignKey("trends.id", ondelete="CASCADE"), nullable=False
)
id_trend_close = Column(
Integer, ForeignKey("trends.id", ondelete="CASCADE"), nullable=False
)
trend_ref = relationship("Trends", foreign_keys=[id_trend_ref])
trend_close = relationship("Trends", foreign_keys=[id_trend_close])
def __str__(self):
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.