Haskell在不更改代碼的情況下刪除數據庫變量

Question

我剛剛意識到我一直在錯誤地進行此操作。

我創建了與testDatabase相關的函數。 我也將其包含在函數中，但是，我想對其進行更改，以便該函數代碼可以在以后的任何數據庫中運行，而不僅僅是與testDatabase有關，因為其中一些函數正在執行此操作。

通過從某些函數中刪除testDatabase ，我會得到錯誤，因此只需要一些幫助來更改和修復此問題，以供將來參考。 我已經吸取了教訓，不要在函數中使用實際的測試數據庫。

我該如何更改代碼，以使testDatabase不在功能中，而在演示中卻與示例1、7和77相似。

我完全更改代碼沒有問題，但是我只是在尋找快速解決方案。

我希望我已經正確解釋了。

import Data.List 
import Text.Printf
import Data.Ord
import Data.Char

type Rating = (String, Int)
type Title = String
type Director = String
type Year = Int
type Film = (Title, Director, Year,[Rating])

testDatabase :: [Film]
testDatabase = [("Blade Runner","Ridley Scott",1982,[("Amy",6), ("Bill",9), ("Ian",7), ("Kevin",9), ("Emma",4), ("Sam",5), ("Megan",4)]),
                ("The Fly","David Cronenberg",1986,[("Megan",4), ("Fred",7), ("Chris",5), ("Ian",0), ("Amy",5)]),
                ("Psycho","Alfred Hitchcock",1960,[("Bill",4), ("Jo",4), ("Garry",8), ("Kevin",7), ("Olga",8), ("Liz",10), ("Ian",9)]),
                ("Body Of Lies","Ridley Scott",2008,[("Sam",3), ("Neal",7), ("Kevin",2), ("Chris",5), ("Olga",6)]),
                ("Avatar","James Cameron",2009,[("Olga",2), ("Wally",8), ("Megan",9), ("Tim",5), ("Zoe",8), ("Emma",3)]),
                ("Titanic","James Cameron",1997,[("Zoe",7), ("Amy",2), ("Emma",5), ("Heidi",3), ("Jo",8), ("Megan",5), ("Olga",7), ("Tim",10)]),
                ("The Departed","Martin Scorsese",2006,[("Heidi",2), ("Jo",8), ("Megan",5), ("Tim",2), ("Fred",5)]),
                ("Aliens","Ridley Scott",1986,[("Fred",8), ("Dave",6), ("Amy",10), ("Bill",7), ("Wally",2), ("Zoe",5)]),
                ("Prometheus","Ridley Scott",2012,[("Garry",3), ("Chris",4), ("Emma",5), ("Bill",1), ("Dave",3)]),
                ("E.T. The Extra-Terrestrial","Steven Spielberg",1982,[("Ian",7), ("Amy",2), ("Emma",7), ("Sam",8), ("Wally",5), ("Zoe",6)]),
                ("The Birds","Alfred Hitchcock",1963,[("Garry",7), ("Kevin",9), ("Olga",4), ("Tim",7), ("Wally",3)]),
                ("Goodfellas","Martin Scorsese",1990,[("Emma",7), ("Sam",9), ("Wally",5), ("Dave",3)]),
                ("The Shawshank Redemption","Frank Darabont",1994,[("Jo",8), ("Sam",10), ("Zoe",3), ("Dave",7), ("Emma",3), ("Garry",10), ("Kevin",7)]),
                ("Gladiator","Ridley Scott",2000,[("Garry",7), ("Ian",4), ("Neal",6), ("Wally",3), ("Emma",4)]),
                ("The Green Mile","Frank Darabont",1999,[("Sam",3), ("Zoe",4), ("Dave",8), ("Wally",5), ("Jo",5)]),
                ("True Lies","James Cameron",1994,[("Dave",3), ("Kevin",4), ("Jo",0)]),
                ("Minority Report","Steven Spielberg",2002,[("Dave",5), ("Garry",6), ("Megan",2), ("Sam",7), ("Wally",8)]),
                ("The Wolf of Wall Street","Martin Scorsese",2013,[("Dave",6), ("Garry",6), ("Megan",0), ("Sam",4)]),
                ("War Horse","Steven Spielberg",2011,[("Dave",6), ("Garry",6), ("Megan",3), ("Sam",7), ("Wally",8), ("Zoe",8)]),
                ("Lincoln","Steven Spielberg",2012,[("Ian",3), ("Sam",7), ("Wally",3), ("Zoe",4), ("Liz",7), ("Megan",4)]),
                ("Vertigo","Alfred Hitchcock",1958,[("Bill",7), ("Emma",5), ("Zoe",9), ("Olga",6), ("Tim",10)]),
                ("The Terminal","Steven Spielberg",2004,[("Olga",3), ("Heidi",8), ("Bill",2), ("Sam",6), ("Garry",8)]),
                ("Jaws","Steven Spielberg",1975,[("Fred",3), ("Garry",0), ("Jo",3), ("Neal",9), ("Emma",7)]),
                ("Hugo","Martin Scorsese",2011,[("Sam",4), ("Wally",3), ("Zoe",4), ("Liz",7)])] 

------------------------------------------------------------
-----------------FUNCTIONAL CODE----------------------------
------------------------------------------------------------                

--when adding need to be addFilm string string int and the list name called testDatabase 
addFilm :: String -> String -> Int -> [Film] -> [Film]
addFilm title director year database = (title, director, year, [])  : database  

--Some functions needed later on:
averageFilmRating :: [(String,Int)] -> Float
averageFilmRating ratings
     = (fromIntegral(sum $ map snd ratings)) / (fromIntegral(length ratings))

--Formats the films for decimal, gives average rating of films instead of all users ratings.
formatFilmOutput :: Film -> String
formatFilmOutput (title, director, year, rating)
     = printf "%s by %s. Year: %d, Average Rating: %.1f\n" (title) (director) (year) (averageFilmRating rating)

--Shows all films in the database    
displayAllFilm :: [Film] -> [Film]
displayAllFilm list = list


--Shows films by director name
displayByDirector :: String -> [Film]
displayByDirector name
     =  filter(\(_,director,_,_) -> director == name) testDatabase

--Gives the average of directors films  
directorAverage :: String -> Float
directorAverage dir
     = averageFilmRating [rating | (title, director, year, ratings) <- displayByDirector dir, rating <- ratings]

--These two functions give the films rated of average 6 or over  
filmsRated :: Int -> [Film]
filmsRated rating
         = filter(\(_,_,_,a) -> averageFilmRating a >= fromIntegral rating) testDatabase 

filmsaveragesix = filmsRated 6  

--Shows what films the user has rated.
userRatedFilms :: String -> [Film]
userRatedFilms username
     = filter ((username `elem`) . (\(_,_,_,xs) -> map fst xs)) testDatabase

-- Allows user to rate or re-rate film.
databaseNoFilm:: [Film] -> Title -> [Film]
databaseNoFilm database t = [(title, director, year, ratings) | (title, director, year, ratings) <- database, title /= t]
rateFilm :: [Film] -> Title -> Rating -> [Film]
rateFilm database findtitle (u, r) = databaseNoFilm database findtitle ++ [(title,director,year,(u, r):[(username,rtg) | (username,rtg) <- ratings, username /= u]) | (title, director, year, ratings) <- database, title == findtitle] 

--Displays films by year in descending order of rating
filmsByYear :: Int -> [Film]
filmsByYear year = sortFilms $ filter(\(_,_,yr,_) -> yr >= year) testDatabase

sortFilms :: [Film] -> [Film]
sortFilms = sortBy $ flip $ comparing averageFilmRating'
  where
    averageFilmRating' (_,_,_,rs) = averageFilmRating rs

------------------------------------------------------------
-----------------DEMO FUNCTION------------------------------
------------------------------------------------------------
demo :: Int -> IO ()
demo choice = do
    case choice of
        1 -> do
            putStrLn $ unlines $ map formatFilmOutput $ addFilm "Gravity" "Alfonso Cuaron" 2013 testDatabase
        2 -> do
            putStrLn (unlines $ map formatFilmOutput $ displayAllFilm testDatabase)
        3 -> do
            putStrLn (unlines (map formatFilmOutput(displayByDirector "James Cameron")))
        4 -> do
            putStrLn (unlines (map formatFilmOutput(filmsaveragesix)))
        5 -> do
            print $ directorAverage "James Cameron"
        6 -> do
            print $ userRatedFilms "Zoe"
        7 -> do
            print $ rateFilm testDatabase "Jaws" ("Zoe", 8)
        77 -> do
            print $ rateFilm testDatabase "Vertigo" ("Zoe", 3)          
        8 -> do
            putStrLn (unlines (map formatFilmOutput(filmsByYear 2009)))

Answer 1

發送testDatabase作為參數。 例如：

--Displays films by year in descending order of rating
filmsByYear :: Int -> [Film] -> [Film]
filmsByYear year database = sortFilms $ filter(\(_,_,yr,_) -> yr >= year) database

然后將testDatabase添加到任何調用此函數的代碼中：

putStrLn (unlines (map formatFilmOutput(filmsByYear 2009 testDatabase)))

在userRatedFilms和displayByDirector執行相同的displayByDirector 。