[英]How to make a sleep thread in For loop?
我正在制作一個紙牌游戲應用程序,我完成了基本的東西,現在我想讓它看起來很專業。 我想要做的第一件事是卡的分配效果,我想做一個隨機卡片效果。 當一張牌給玩家時,我希望與下一張分發給他的牌相差至少500毫秒。 想法? 這是我的代碼的一部分..
private void SetTheGame() {
SetShuffleSound();
for ( int i = 0; i < Imagename.length;i++) {
Imagename[i] = (ImageView) findViewById(WTF[i]);
CountCards();
Random = getRandom();
SwitchImages SwitchMe = new SwitchImages(myNewArray[Random]);
int first = SwitchMe.ChangeImages();
Imagename[i].setImageResource(myNewArray[Random]);
Imagename[i].setVisibility(View.VISIBLE);
CardsCount valueOfCard = new CardsCount(myNewArray[Random]);
int a = valueOfCard.WhatsMyValue();
String b = valueOfCard.TheFamily();
switch (i) {
case 0:
if (first != 0) {
Imagename[0].setImageResource(first);
}
FirstColumnComputer.add(a);
FirstColumnComputerFAMILY.add(b);
break;
case 1:
if (first != 0) {
Imagename[1].setImageResource(first);
}
SecondColumnComputer.add(a);
SecondColumnComputerFAMILY.add(b);
break;
case 2:
if (first != 0) {
Imagename[2].setImageResource(first);
}
ThirdColumnComputer.add(a);
ThirdColumnComputerFAMILY.add(b);
break;
case 3:
if (first != 0) {
Imagename[3].setImageResource(first);
}
FourColumnComputer.add(a);
FourColumnComputerFAMILY.add(b);
break;
case 4:
if (first != 0) {
Imagename[4].setImageResource(first);
}
FifthColumnComputer.add(a);
FifthColumnComputerFAMILY.add(b);
break;
case 5:
FirstColumnPlayer.add(a);
FirstColumnPlayerFAMILY.add(b);
break;
case 6:
SecondColumnPlayer.add(a);
SecondColumnPlayerFAMILY.add(b);
break;
case 7:
ThirdColumnPlayer.add(a);
ThirdColumnPlayerFAMILY.add(b);
break;
case 8:
FourColumnPlayer.add(a);
FourColumnPlayerFAMILY.add(b);
break;
case 9:
FifthColumnPlayer.add(a);
FifthColumnPlayerFAMILY.add(b);
break;
}
Cards.remove(Random);
// MakeTheCardPause();
}
SentTheLinkedList();
}
MakeTheCardPause()是問題......
private void MakeTheCardPause() {
Thread Timer = new Thread()
{
public void run()
{
try{
sleep(1000);
}catch(InterruptedException e)
{
e.printStackTrace();
}finally
{
//do something...
}
}
};
Timer.start();
}
謝謝!
你可以用很多方法做到這一點。 Thread.sleep(500)是你建議的方式,但它不是我推薦的。 這有兩種選擇
一個例子
Handler mHandler = new Handler(){
public void handleMessage(Message msg){
super.handleMessage(msg);
switch(msg.what){
case shuffle:
// Do something
break;
case doneShuffle:
//Do something
}
}
};
這是一個例子:
private class shuffleCards extends AsyncTask<Card, Integer, Long> {
protected Long doInBackground(Card card) {
//Do something
//shuffle deck
// Escape early if cancel() is called
if (isCancelled()) break;
}
return deck;
}
protected void onProgressUpdate(Integer... progress) {
//Number of shuffled cards??
}
protected void onPostExecute(Long result) {
//Show card
}
}
請記住,這只是顯示結果的后台任務。 您的主線程將處理實際的卡值並將它們交給Asynch任務。
祝好運
那這個呢? 你需要在工作線程中進行休眠,上面的代碼是創建一個新線程並告訴它睡眠,這對用戶沒有明顯的影響。
private void SetTheGame() {
SetShuffleSound();
for ( int i = 0; i < Imagename.length;i++) {
Imagename[i] = (ImageView) findViewById(WTF[i]);
CountCards();
Random = getRandom();
SwitchImages SwitchMe = new SwitchImages(myNewArray[Random]);
int first = SwitchMe.ChangeImages();
Imagename[i].setImageResource(myNewArray[Random]);
Imagename[i].setVisibility(View.VISIBLE);
CardsCount valueOfCard = new CardsCount(myNewArray[Random]);
int a = valueOfCard.WhatsMyValue();
String b = valueOfCard.TheFamily();
switch (i) {
case 0:
if (first != 0) {
Imagename[0].setImageResource(first);
}
FirstColumnComputer.add(a);
FirstColumnComputerFAMILY.add(b);
break;
case 1:
if (first != 0) {
Imagename[1].setImageResource(first);
}
SecondColumnComputer.add(a);
SecondColumnComputerFAMILY.add(b);
break;
case 2:
if (first != 0) {
Imagename[2].setImageResource(first);
}
ThirdColumnComputer.add(a);
ThirdColumnComputerFAMILY.add(b);
break;
case 3:
if (first != 0) {
Imagename[3].setImageResource(first);
}
FourColumnComputer.add(a);
FourColumnComputerFAMILY.add(b);
break;
case 4:
if (first != 0) {
Imagename[4].setImageResource(first);
}
FifthColumnComputer.add(a);
FifthColumnComputerFAMILY.add(b);
break;
case 5:
FirstColumnPlayer.add(a);
FirstColumnPlayerFAMILY.add(b);
break;
case 6:
SecondColumnPlayer.add(a);
SecondColumnPlayerFAMILY.add(b);
break;
case 7:
ThirdColumnPlayer.add(a);
ThirdColumnPlayerFAMILY.add(b);
break;
case 8:
FourColumnPlayer.add(a);
FourColumnPlayerFAMILY.add(b);
break;
case 9:
FifthColumnPlayer.add(a);
FifthColumnPlayerFAMILY.add(b);
break;
}
Cards.remove(Random);
long sleepMax = 1000L;
Random r = new Random();
long delay = (long) (r.nextDouble() * range);
Thread.sleep(delay);
}
SentTheLinkedList();
}
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