如何在最后一個整數之間添加“和”

Question

我有以下代碼：

def guess_index(guess, word):   
    word2 = list(word)
    num = word.count(guess)+1
    count = 0
    x = []
    for i in range(0,num):
        try:
            count += 1
            y = word2.index(guess)
            x.append(y+count)
            del(word2[y])
        except ValueError:
            break
    z = ",".join(str(i)for i in x)

return "The character you guessed is number %s in the word you have to guess" % (z)

我希望我的z字符串中的最后一個整數具有和，因此它將打印為The character you guessed is number 1,2,3 and 7 in the word you have to guess 。 正確方向的任何指示都將非常有幫助。 謝謝。

Answer 1

您可以切片x以保留最后一個，然后手動添加。 由於切片對負索引的工作方式，請確保檢查列表是否為空或僅包含一個元素：

z = (','.join(str(i) for i in x[:-1]) + " and " + str(x[-1])) if len(x) > 1 else '' if len(x) == 0 else str(x[0])

例：

>>> x = [1, 2, 3, 7]
>>> z = (','.join(str(i) for i in x[:-1]) + " and " + str(x[-1])) if len(x) > 1 else '' if len(x) == 0 else str(x[0])
>>> z
'1,2,3 and 7'

盡管我強烈建議添加牛津逗號並使用一些空格，但要很漂亮：

z = (', '.join(str(i) for i in x[:-1]) + ", and " + str(x[-1])) if len(x) > 1 else '' if len(x) == 0 else str(x[0])

可以寫成：

if len(x) > 1:
    z = ', '.join(str(i) for i in x[:-1]) + ", and " + str(x[-1])
elif len(x) == 1:
    z = str(x[0])
else:
    z = ''