在使用dbClient時插入大量值

Question

目前我正在嘗試在我的新項目中插入很多值，但我無法弄清楚如何做到這一點。 我的“最簡單”的SQL查詢如下所示，此函數的工作原理如下：

dbClient.setQuery("INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`,     `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES " +
"('private', 'VIP CADEAU: Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 0, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');");
dbClient.addParameter("username", Session.GetHabbo().Username);
dbClient.runQuery();     

但是現在我想插入多個值，並使用以下查詢：

INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`, `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1'),

此后數以千計的其他行...

但我完全不知道如何運行自適應我的代碼（ dbClient ）使其工作....一個邏輯但凌亂的解決方案可能是：

dbClient.setQuery("INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`,     `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES " +
    "('private', 'VIP CADEAU: Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 0, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');");
dbClient.setQuery("INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`,     `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES " +
    "('private', 'VIP CADEAU: Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 0, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');");

但我不想在我的代碼中重復1000次'INSERT INTO'。

Answer 1

選項：

• 循環，使用簡單的代碼很多次使用不同的參數
• 使用一個可以為你做到這一點的工具（dapper在那里有一些接近基本的技巧，大多數ORM將允許簡單的基於列表的插入）
• 對於非常大的插入，如果您的提供者支持它，則“批量復制” - 可能使用FastMember將列表轉換為IDataReader

Answer 2

您只需要多個INSERT語句：

INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`, `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');

INSERT INTO `rooms` (`roomtype`, `caption`, `owner`, `description`, `category`, `state`, `users_now`, `users_max`, `model_name`, `public_ccts`, `score`, `tags`, `icon_bg`, `icon_fg`, `icon_items`, `password`, `wallpaper`, `floor`, `landscape`, `allow_pets`, `allow_pets_eat`, `allow_walkthrough`, `allow_hidewall`, `wallthick`, `floorthick`, `achievement`, `group_id`, `game_id`, `mute_settings`, `ban_settings`, `kick_settings`) VALUES
('private', 'Penthouse', @username, 'Ontvang deze kamer GRATIS bij het lid worden van VIP (http://wonderhotel.nl/vip).', 11, 'open', 7, 25, 'model_i', '', 1, '', 1, 0, '', '', '0.0', '0.0', '0.0', '1', '0', '0', '0', -2, -2, 0, 0, 0, '0', '1', '1');