[英]Serialize List Elements in XML without class name
我下面的課:
public class Family
{
public List<ChildAge> childAges { get; set; }
}
現在,ChildAge如下所示:
public class ChildAge
{
public int Age { get; set; }
}
當我將此序列化為XML時,我得到:
<root>
<Family>
<ChildAges>
<ChildAge>
<Age>10</Age>
</ChildAge>
<ChildAge>
<Age>8</Age>
</ChildAge>
</ChildAges>
</Family>
</root>
我需要更改以獲得以下內容:
<root>
<Family>
<ChildAges>
<Age>10</Age>
<Age>8</Age>
</ChildAges>
</Family>
<root>
謝謝!
您可以通過提供自己的WriteXml實現來做到這一點(以及更多)。
請看下面的代碼。
public class Family : IXmlSerializable
{
public List<ChildAge> childAges { get; set; }
public void WriteXml(XmlWriter writer)
{
foreach(ChildAge ca in childAges)
writer.WriteElementString("Age", ca.Age.ToString());
}
public void ReadXml(XmlReader reader)
{
// [...]
}
public XmlSchema GetSchema()
{
return (null);
}
}
public class ChildAge
{
public int Age { get; set; }
}
public class Program
{
static void Main(string[] args)
{
Family f = new Family();
f.childAges = new List<ChildAge>();
f.childAges.Add(new ChildAge() { Age = 10 });
f.childAges.Add(new ChildAge() { Age = 8 });
XmlSerializer xs = new XmlSerializer(typeof(Family));
XmlSerializerNamespaces xmlnsEmpty;
xmlnsEmpty = new XmlSerializerNamespaces(new[] { XmlQualifiedName.Empty });
XmlWriterSettings writerSettings = new XmlWriterSettings();
writerSettings.Indent = true;
writerSettings.OmitXmlDeclaration = true;
StringBuilder sb = new StringBuilder();
XmlWriter writer = XmlTextWriter.Create(sb, writerSettings);
xs.Serialize(writer, f, xmlnsEmpty);
Console.WriteLine(sb.ToString());
Console.ReadLine();
}
}
一旦在“子項”下有更多要序列化的屬性,您的問題就會開始,您只需使用列表和以下注釋即可:
[XmlArray("ChildAges")]
[XmlArrayItem("Age")]
List<int> ChildrenAges { get; set; }
你已經完成了
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