如何在SQL Server存儲過程中使用逗號分隔（拆分）字符串

Question

我有一個checkboxlist 。 所選（已選中）項目存儲在List<string> selected 。

例如，選擇的值是monday,tuesday,thursday ，7天

我正在將List<>轉換為以逗號分隔的string ，即

string a= "monday,tuesday,thursday"

現在，我將此值作為字符串傳遞給存儲過程。 我想解雇像：

Select * 
from tblx 
where days = 'Monday' or days = 'Tuesday' or days = 'Thursday'`

我的問題是：如何在存儲過程中分離字符串？

Answer 1

如果您將逗號分隔（任何分隔符）字符串傳遞給存儲過程並在查詢中使用，那么必須吐出該字符串然后您將使用它。

下面有例子：

DECLARE @str VARCHAR(500) = 'monday,tuesday,thursday'
CREATE TABLE #Temp (tDay VARCHAR(100))
WHILE LEN(@str) > 0
BEGIN
    DECLARE @TDay VARCHAR(100)
    IF CHARINDEX(',',@str) > 0
        SET  @TDay = SUBSTRING(@str,0,CHARINDEX(',',@str))
    ELSE
        BEGIN
        SET  @TDay = @str
        SET @str = ''
        END
  INSERT INTO  #Temp VALUES (@TDay)
 SET @str = REPLACE(@str,@TDay + ',' , '')
 END

 SELECT * 
 FROM tblx 
 WHERE days IN (SELECT tDay FROM #Temp)

Answer 2

嘗試這個

CREATE FUNCTION Split
(
  @delimited nvarchar(max),
  @delimiter nvarchar(100)
) RETURNS @t TABLE
(
-- Id column can be commented out, not required for sql splitting string
  id int identity(1,1), -- I use this column for numbering splitted parts
  val nvarchar(max)
)
AS
BEGIN
  declare @xml xml
  set @xml = N'<root><r>' + replace(@delimited,@delimiter,'</r><r>') + '</r></root>'

  insert into @t(val)
  select
    r.value('.','varchar(max)') as item
  from @xml.nodes('//root/r') as records(r)

  RETURN
END
GO

用法：

select * from tblx where days in (select val from dbo.split('monday,tuesday,thursday',','))

Answer 3

我想你想要這個

SELECT * FROM tblx where days in ('Monday','Tuesday','Thursday')

你可以這樣得到它：

var a = "monday,tuesday,thursday";
var sql = string.Format("Select * from tblx where days IN ('{0}')", string.Join("','",a.Split(new[] {','})));

Answer 4

嘗試這個：

CREATE FUNCTION [dbo].[ufnSplit] (@string NVARCHAR(MAX))
RETURNS @parsedString TABLE (id NVARCHAR(MAX))
AS 
BEGIN
   DECLARE @separator NCHAR(1)
   SET @separator=','
   DECLARE @position int
   SET @position = 1
   SET @string = @string + @separator
   WHILE charindex(@separator,@string,@position) <> 0
      BEGIN
         INSERT into @parsedString
         SELECT substring(@string, @position, charindex(@separator,@string,@position) - @position)
         SET @position = charindex(@separator,@string,@position) + 1
      END
     RETURN
END

然后使用這個功能，

Select * 
from tblx 
where days IN (SELECT id FROM [dbo].[ufnSplit]('monday,tuesday,thursday'))

Answer 5

我面臨同樣的問題，我一直嘗試但沒有得到預期的解決方案。 最后我確實喜歡跟隨。 試試希望它會起作用......

create Function [dbo].[Split]
(
   @RowData NVARCHAR(MAX),
   @SplitOn NVARCHAR(5)
)
RETURNS @RtnValue TABLE
(
   Id INT IDENTITY(1,1),
   Data NVARCHAR(100)
)
AS
BEGIN 
   DECLARE @Cnt INT
   SET @Cnt = 1
   WHILE (Charindex(@SplitOn,@RowData)>0)
   BEGIN
          INSERT INTO @RtnValue (data)
          SELECT Data = ltrim(rtrim(Substring(@RowData,1,Charindex(@SplitOn,@RowData)-1)))
          SET @RowData = Substring(@RowData,Charindex(@SplitOn,@RowData)+1,len(@RowData))
          SET @Cnt = @Cnt + 1
   END
   INSERT INTO @RtnValue (data)
   SELECT Data = ltrim(rtrim(@RowData))
   RETURN
END

並在商店程序中放置這樣的代碼。

select @ActualTarget= count(*) from UpdateVisitDetails where CreatedBy IN (SELECT [DATA] FROM [dbo].[Split](@AllDATS,',' ))

Answer 6

我有同樣的問題。 我試過這個..這是正確的運行

ALTER FUNCTION [dbo].[Split]
(
  @List varchar(max),
  @SplitOn nvarchar(5)
)

RETURNS @RtnValue table
(
  Id int identity(1,1),
  Value nvarchar(max)
)
AS
BEGIN
IF (len(@List) <=0)
Begin
Return 
End

While (Charindex(@SplitOn,@List)>0)
Begin

Insert Into @RtnValue (value)
Select
Value = ltrim(rtrim(Substring(@List,1,Charindex(@SplitOn,@List)-1)))

Set @List = Substring(@List,Charindex(@SplitOn,@List)+len(@SplitOn),len(@List))
End

Insert Into @RtnValue (Value)
Select Value = ltrim(rtrim(@List))

Return
END

Run : 
SELECT * FROM dbo.Split('Apple,Banana,Mango',',')

輸出：