Python Pygame形狀旋轉問題

Question

我對Pygame相當陌生，我正在嘗試制作一個簡單的小游戲，我目前在旋轉矩形時遇到問題。 它自身的形狀會旋轉，但是由於某種原因，當形狀旋轉時（例如說90度），它會從地板上浮出幾個像素，這是一個圖像，說明發生了什么：

    #Player Class
class Player(pygame.sprite.Sprite):
    """ This class represents the bar at the bottom that the player
        controls. """


    # List of sprites we can bump against
    level = None

    # -- Methods
    def __init__(self):
        """ Constructor function """

        # Call the parent's constructor
        pygame.sprite.Sprite.__init__(self)

        # Create an image of the block, and fill it with a color.
        # This could also be an image loaded from the disk.
        self.width = 40
        self.height = 60
        self.image = pygame.Surface([self.width, self.height])
        self.image.fill(RED)
        self.baseImage = self.image        

        # Set a referance to the image rect.
        self.rect = self.image.get_rect()
    def update(self):
        """ Move the player. """

        # Move left/right
        self.rect.x += self.change_x

        # See if we hit anything
        block_hit_list = pygame.sprite.spritecollide(self, self.level.platform_list, False)
        for block in block_hit_list:
            # If we are moving right,
            # set our right side to the left side of the item we hit
            if self.change_x > 0:
                self.rect.right = block.rect.left
            elif self.change_x < 0:
                # Otherwise if we are moving left, do the opposite.
                self.rect.left = block.rect.right

    # Player-controlled movement:
    def go_left(self):
        """ Called when the user hits the left arrow. """
        self.change_x = -10

    def go_right(self):
        """ Called when the user hits the right arrow. """
        self.change_x = 10

    def stop(self):
        """ Called when the user lets off the keyboard. """
        self.change_x = 0

    def turn_r(self):       
        self.image = pygame.transform.rotate(self.image, angle)
        self.change_x = 0

    def turn_l(self):
        count = -90
        self.image = pygame.transform.rotate(self.image, angle)
        self.change_x = -0

＃--------主程序循環-----------

 while not done:
        for event in pygame.event.get(): # User did something
            if event.type == pygame.QUIT: # If user clicked close
                done = True # Flag that we are done so we exit this loop

            if event.type == pygame.KEYDOWN:
                if event.key == pygame.K_LEFT:
                    player.go_left()                
                if event.key == pygame.K_RIGHT:
                    player.go_right()
                if event.key == pygame.K_UP:
                    player.jump()
                if event.key == pygame.K_d:
                    player.turn_r()
                    count += 90
                if event.key == pygame.K_a:
                    player.turn_l()
                    count -= 90

Answer 1

您的問題似乎在形狀的頂部和左側，您可能需要重新對齊中心，例如：

def turn_r(self):       
    center_x = self.rect.x + (self.rect.width / 2)
    center_y = self.rect.y + (self.rect.height / 2)

    self.image = pygame.transform.rotate(self.image, angle)

    new_center_x = self.rect.x + (self.rect.width / 2)
    new_center_y = self.rect.y + (self.rect.height / 2)

    self.change_x = center_x - new_center_x
    self.change_y = center_y - new_center_y

或者，您可以將形狀的新Y設置為返回到底部：

def turn_r(self):       
    bottom = self.rect.y + self.rect.height
    self.image = pygame.transform.rotate(self.image, angle)
    new_bottom = self.rect.y + self.rect.height
    self.change_y = bottom - new_bottom

我對PyGame不太了解，代碼可能會有一些問題，但這是這樣的。

Answer 2

在將其旋轉90°之前，寬度為40，高度為60。將其交換后，這兩個值被交換，因此現在高度僅為40，而您的代碼仍將其以參考原始60像素的高度旋轉。

我想說的最簡單的方法是使程序旋轉圖像並重置為另一個高度級別，該高度級別比以前降低了20個像素。

Answer 3

只是為了幫助別人，我才弄清楚代碼出了什么問題。 問題是，形狀旋轉后，矩形保持不變，我通過在turn_r和turn_l函數中簡單地更新了矩形來解決了這個問題。 隨時尋求幫助！