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如何使用空列值對mysql表排序

[英]How to sort a mysql table with null column values

我有一個具有以下架構的表。 我需要按對表進行排序,如果存在img_link (不為null )的行也排在第一位。 只需要做的就是按int列排序,然后按varchar列排序。

+-----+--------+-----------+-----------+
| id  | name   | img_link  |  points   |
+-----+--------+-----------+-----------+
| 11  | smpl   | path.jpg  |  10       |
+-----+--------+-----------+-----------+
| 12  | main   |  null     |  20       |
+-----+--------+-----------+-----------+
| 13  | abcd   |  null     |  10       |
+-----+--------+-----------+-----------+
| 14  | xyls   | img_.png  |  10       |
+-----+--------+-----------+-----------+

需要一個類似的結果

+-----+
| id  |
+-----+
| 12  |
+-----+
| 11  |
+-----+
| 14  |
+-----+
| 13  |
+-----+

提前致謝..

嘗試這個

SELECT * FROM table_name ORDER BY points DESC ,ISNULL(img_link), img_link 

基本上,您用言語准確地寫下了您需要做的事情。

SELECT id FROM someTable ORDER BY points DESC, img_link DESC;

DEMO

另一種方法是

select *
from table
order by `points` desc,
if(img_link = '' or img_link is null,1,0)

DEMO

嘗試這個:

select * from tabalename where img_link is not null order by point desc union select * from tabalename where img_link is null order by point desc
SELECT * FROM my_table ORDER BY points DESC, img_link IS NULL, img_link DESC;

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