[英]cURL post to HTTPCLient C#
我正在嘗試將文件發布到PushBullet API服務。
API的信息站點顯示了一個示例:
curl -i https://api.pushbullet.com/api/pushes \
-u API_KEY:
-F device_iden=u1qSJddxeKwOGuGW
-F type=file
-F file=@test.txt
我正在嘗試使用C#的HttpClient
進行操作
我知道如何使用Httpclient
和MultipartFormDataContent
來發布文件,但是如何添加device_iden並在客戶端中輸入信息?
我正在用這個
using (var content = new MultipartFormDataContent())
{
try
{
content.Add(new StreamContent(new FileStream(pathFile, FileMode.Open, FileAccess.Read)));
var resp = wc.PostAsync(new Uri(baseUri, "api/pushes"), content);
}
catch (Exception)
{
throw;
}
}
[[新添加]]
使用cURL和fiddler這將是POST
POST http://\/ HTTP/1.1
Authorization: Basic d45YQkxueWswSmxQRTYFjc1deUzNo8UtueVZpaktIZm34anVqdU9NZerWYmFlOp==
User-Agent: curl/7.33.0
Host: \
Accept: */*
Proxy-Connection: Keep-Alive
Content-Length: 787
Expect: 100-continue
Content-Type: multipart/form-data; boundary=------------------------886f3981539a91b3
--------------------------886f3981539a91b3
Content-Disposition: form-data; name="device_iden"
ujuOMfjVbaedjz7O3P0Jl6
--------------------------886f3981539a91b3
Content-Disposition: form-data; name="type"
file
--------------------------886f3981539a91b3
Content-Disposition: form-data; name="file"; filename="img.gif"
Content-Type: application/octet-stream
GIF89a������@�;A�;A�;A�;B�<B�<������!�Created with GIMP�!�
��,����������x�����I��8KȻ�`(�$��h��l{�p�tm߮��x����P,���҃l:q���I���u�Mf����
��d�y}LG��{���J�>���W};������^�1�����������
--------------------------886f3981539a91b3--
在嘗試了提琴手之后,終於可以發表那篇文章了:
第一:
public static void PushFile(string pathFile, string iddev)
{
string name = Path.GetFileName(pathFile);
using (var wc = GetClient())
{
using (var multiPartCont = new MultipartFormDataContent())
{
multiPartCont.Add(addStringContent("device_iden", iddev));
multiPartCont.Add(addStringContent("type","file"));
multiPartCont.Add(addStreamContent(new FileStream(pathFile,FileMode.Open),name ));
try
{
var resp = wc.PostAsync(new Uri(baseUri, "api/pushes"), multiPartCont);
Task<string> result = resp.Result.Content.ReadAsStringAsync();
//string resultado = result.Result;
}
catch (Exception)
{
throw;
}
}
}
}
然后創建字符串內容和流內容的方法
private static StreamContent addStreamContent(Stream stream, string filename )
{
var fileContent = new StreamContent(stream);
fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "\"file\"",
FileName = "\""+filename+"\""
};
fileContent.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
return fileContent;
}
private static StringContent addStringContent(string name, string content)
{
var fileContent = new StringContent(content);
fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "\"" + name + "\""
};
return fileContent;
}
curl中的-u是http認證。 看來pushbullet希望您使用API密鑰登錄。 使用httpclient,您將使用;
httpClient.DefaultRequestHeaders.Authorization = CreateBasicHeader("username", "password");
其余的將是GET或POST變量(我不確定pushbullet期望什么)。 看起來在您的代碼中已使用POST對其進行了設置。 因此,您可以使用;
"device_iden=u1qSJddxeKwOGuGW&type=file";
創建-u
數據的另一種方法是使用NetworkCredential
創建HttpClientHandler
。
var handler = new HttpClientHandler
{
Credentials = new NetworkCredential(API_KEY, "")
};
var client = new HttpClient(handler);
這將創建一個基本的HTTP身份驗證標頭
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