[英]Inserting Array values from form into mysql
我有3個PHP文件,在select.php文件中,您必須選擇所需的表單數量。該表單包含3個輸入字段。 如下:
<form method="post" action="index.php" >
Continue insertion with <select name="counters" id="insert_rows">
<option value="1">1</option>
<option value="2" selected="selected">2</option>
<option value="3">3</option>
</select>
rows
<input type="submit" value="Go" />
</form>
選擇插入次數后,它將把該數目傳遞給包含以下內容的index.php:
<?php
echo "<form method = 'POST' action = 'process.php'>";
for($counter = 0; $counter < $_POST['counters']; $counter++)
{
echo "Service Name: <input type = 'text' name = 'name[]' class = 'class_name'/><br/>";
echo "Service Version : <input type = 'text' name = 'version[]' class = 'class_name'/><br/>";
echo "Service type : <input type = 'text' name = 'type[]' class = 'class_name'/><br/>";
}
echo "<input type = 'submit' value = 'SEND'/>";
echo "</form>";
?>
第三個文件process.php包含
<?php
$name = array();
$version = array();
$type= array();
$name = $_POST['name'];
$version = $_POST['version'];
$type= $_POST['type'];
for($counter = 0; $counter < sizeof($name); $counter++)
{
echo "service_name #".($counter + 1).": ".$name[$counter]."<br />";
echo "service_version #".($counter + 1).": ".$version[$counter]."<br />";
echo "service_type #".($counter + 1).": ".$type[$counter]."<br />";
}
?>
在我將值傳遞給它之后,它正確顯示了數據,如下所示
service_name#1:否service_version#1:v1 service_type#1:私人service_name#2:bandar service_version#2:v2 service_type#2:公共
所以我的問題是:如何在'process.php'文件中創建一個函數以將所有這些值插入數據庫。
我創建了一個名為“服務”的表,其中包含這些列“名稱,版本,類型”
我將等待您的支持。 謝謝
我建議將第一個提交的計數值保存在第二種形式的隱藏輸入中,這樣您就可以循環瀏覽並插入數據
<?php
echo "<form method = 'POST' action = 'process.php'>";
for($counter = 0; $counter < $_POST['counters']; $counter++)
{
echo "Service Name: <input type = 'text' name = 'name[]' class = 'class_name'/><br/>";
echo "Service Version : <input type = 'text' name = 'version[]' class = 'class_name'/><br/>";
echo "Service type : <input type = 'text' name = 'type[]' class = 'class_name'/><br/>";
}
echo '<input type="hidden" name="cntr" value="'.$_POST['counters'].'" />'
echo "<input type = 'submit' value = 'SEND'/>";
echo "</form>";
?>
現在在您的process.php中,您將擁有:
if (!empty($_POST['cntr'])) {
$query = 'INSERT INTO services (name, version, type) VALUES ';
for ($x = 0; $x < $_POST['cntr']; $x++)
{
$query .= "('".mysqli_escape_string($_POST['name'][$x])."','"
.mysqli_escape_string($_POST['version'][$x])."','"
.mysqli_escape_string($_POST['type'][$x]).
"'),";
}
$query = substr_replace($query, '', -1);
mysqli->query($query);
}
我准備的只是一個示例,您可以根據自己的更改對其進行修改
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