如何退回所有費用的總和？

Question

因此，我從事代碼學院已有一段時間了。 我有一個作業，說我需要返回以前功能的費用總和。 因為這種方式行不通，我該怎么辦？ 以及如何避免將來再遇到此問題？

def hotel_cost(nights)
    nights = raw_input("How many nights are you staying? ")
    if nights == 0:
            return 0
    elif nights > 0:
        return 140 * nights

def plane_ride_cost(city):
    if city == "Charlotte":
        cost = 183
    elif city == "Tampa":
        cost = 220
    elif city == "Pittsburgh":
        cost = 222
    elif city == "Los Angeles":
        cost = 475
    return cost

def rental_car_cost(days):
    days = nights
    cost = days * 40
    if days >= 7:
        cost -= 50
    elif days >= 3:
        cost -= 20
    return cost

def trip_cost(city, days):
    return  rental_car_cost(days) + plane_ride_cost(cost) + hotel_cost(days)

我收到此錯誤：

hotel_cost(1) raised an error:
invalid literal for int() with base 10

Answer 1

nights = raw_input("How many nights are you staying? ")

raw_input返回一個字符串，您需要將其轉換為整數。 使用int(nights) 。

int（）文檔

Answer 2

嘗試這個：

nights = input("How many nights are you staying? ")

input()返回一個int

我認為如果避免在功能內獲取用戶輸入會更好，在這種情況下，您可以在外部功能中收集所有信息，例如：

if __name__ == '__main__':
    days = input('Something..')
    nights = input('Something...')
    city = raw_input('Something...')
    # do whatever you want with data
    print  plane_ride_cost(city) + rental_car_cost(days) + hotel_cost(nights)

不知道您使用此示例的方式...

您可以閱讀有關input（）的內容

Answer 3

如果只希望整數作為輸入，請更改以下行：

nights = raw_input("How many nights are you staying? ")

至：

nights = int(raw_input("How many nights are you staying? "))

這將通過將int()強制轉換為raw_input()來糾正錯誤，該方法返回一個字符串。

>>> x = raw_input()
98
>>> type(x)
<type 'str'>
>>> x = int(raw_input())
23
>>> type(x)
<type 'int'>
>>>