[英]Storing XML file in SQL Server 2008 R2 express
我正在嘗試將XML數據存儲到SQL Server 2008 R2 Express數據庫中,每個xml文件都有不同的數據。 最簡單的方法是什么?
最佳選擇是什么,請舉例說明。
我相信最簡單的方法是創建一個存儲過程來為您處理存儲。 然后,您可以通過首選ORM檢索它,並讓C#為您反序列化它。
CREATE TABLE [dbo].[MyXmlStorage]
(
[Id] [int] IDENTITY(1,1) NOT NULL,
[FileName] [nvarchar](255) NOT NULL,
[Xml] [xml] NOT NULL,
CONSTRAINT [PK_MyXmlStorage]
PRIMARY KEY CLUSTERED ([Id] ASC)
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
CREATE PROCEDURE [dbo].[InsertXml]
(@filePathFull nvarchar(255))
AS
DECLARE @xmlAsString VARCHAR(MAX)
DECLARE @sql nvarchar(max)
DECLARE @xml XML
DECLARE @Rms_FileId nvarchar(50)
DECLARE @Rms_Id nvarchar(50)
DECLARE @Rms_Type nvarchar(50)
DECLARE @Rms_Timestamp nvarchar(50)
BEGIN
SET @sql = 'SELECT @xmlAsString = x.y FROM OPENROWSET( BULK ''' + RTRIM(@filePathFull) + ''', SINGLE_CLOB) x(y)'
exec sp_executesql @sql,N'@xmlAsString VARCHAR(MAX) OUTPUT',@xmlAsString OUTPUT
set @xml = CONVERT(XML,@xmlAsString)
INSERT INTO MyXmlStorage([FileName],[Xml])
VALUES (@filePathFull, @xml)
END
然后像這樣運行它:
exec InsertXml N'C:\files\xmlfile.xml'
好的,這是一個將xml值存儲到表中的示例。 我沒有嘗試過此代碼,但它應該可以工作,但至少它應該闡明如何按預期進行。
/* Imagine your xml looks something like this
<Content>
<Title>Text</Title>
<Value>15</Value>
</Content>
*/
CREATE TABLE [dbo].[MyXmlStorage]
(
[Id] [int] IDENTITY(1,1) NOT NULL,
[Title] [nvarchar](100) NOT NULL,
[Value] int NOT NULL,
CONSTRAINT [PK_MyXmlStorage]
PRIMARY KEY CLUSTERED ([Id] ASC)
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
CREATE PROCEDURE [dbo].[InsertXml]
(@filePathFull nvarchar(255))
AS
DECLARE @xmlAsString VARCHAR(MAX)
DECLARE @sql nvarchar(max)
DECLARE @xml XML
DECLARE @Rms_FileId nvarchar(50)
DECLARE @Rms_Id nvarchar(50)
DECLARE @Rms_Type nvarchar(50)
DECLARE @Rms_Timestamp nvarchar(50)
BEGIN
SET @sql = 'SELECT @xmlAsString = x.y FROM OPENROWSET( BULK ''' + RTRIM(@filePathFull) + ''', SINGLE_CLOB) x(y)'
exec sp_executesql @sql,N'@xmlAsString VARCHAR(MAX) OUTPUT',@xmlAsString OUTPUT
set @xml = CONVERT(XML,@xmlAsString)
/* Use xpath to query nodes for values inside the Content tag*/
INSERT INTO MyXmlStorage([Title],[Value])
SELECT
x.y.value('title[1]/text()[1]', 'nvarchar(100)') AS title,
x.y.value('value[1]/text()[1]', 'int') AS value
FROM @xml.nodes('//Content') AS x(y)
END
)
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