[英]Selecting users,groups and site from alfresco database
我想選擇用戶,他們屬於哪個組以及他們的站點。 我想要一個postgre sql查詢。
我已經找到了這些查詢,但是如果可能的話,我希望將它們與join結合使用。
select * from alf_permission
select * from ALF_AUTHORITY
select * from ALF_CHILD_ASSOC where CHILD_NODE_NAME like ‘group%’
select * from ALF_CHILD_ASSOC where QNAME_LOCALNAME like ‘GROUP%’
select
node_id,
string_agg(string_value, ',')
from (
select
node_id,
qname_id,
(select local_name from alf_qname where id = qname_id) as qname_type,
string_value
from alf_node_properties
where node_id in (
select id from alf_node
where type_qname_id = (
select id from alf_qname where local_name = 'person'
)
and qname_id in (
select id
from alf_qname
where local_name in (
'username',
'firstName',
'lastName',
'email'
)
)
)
) alf_users
group by node_id;
我建議盡可能用Java創建網絡腳本,以實現快速高效的操作!
我找到了解決方案! 我將腳本放在公司主頁>數據字典> Web腳本>組織>露天>測試
如您所見,我在“ alfresco”文件夾中創建了“ test”文件夾,並在其中放置了這三個文件。
hello.get.html.ftl文件
<table border>
<tr>
<th>Username</th>
<th>Groups</th>
<th>Sites</th>
</tr>
<#list test as child>
<tr>
<td>${child['username']}</td>
<td>${child['groups']}</td>
<td>${child['sites']}</td>
</tr>
</#list>
</table>
hello.get.desc.xml
<webscript>
<shortname>Hello</shortname>
<description>Polite greeting</description>
<url>/test/hello</url>
<authentication>user</authentication>
</webscript>
hello.get.js
var gens = search.luceneSearch("TYPE:\"{http://www.alfresco.org/model/content/1.0}person\"");
var a = [];
for (var i=0; i<gens.length;i++) {
var username = gens[i].properties["cm:userName"];
var b = [];
var groups = people.getContainerGroups(gens[i]);
for(var j=0; j<groups.length; j++) {
b.push(groups[j].properties['authorityDisplayName']);
}
var sites = siteService.listUserSites(username);
var g=[]
for(var j=0; j<sites.length; j++) {
g.push(sites[j]['shortName']);
}
//a.push('\n\n\n'+username+'\groups--> '+ b.join(', ') + '\nsites--> '+g.join(', '));
a.push({
'username' : username,
'groups' : b.join(', '),
'sites' : g.join(', ')
})
}
model.test = a;
您可以在your_domain_name / alfresco / service / test / hello中訪問結果
嘗試此查詢以獲取人員和組
select
ca.id,
ca.parent_node_id,
ca.child_node_id,
ca.qname_localname,
np.string_value
from alf_child_assoc as ca
join alf_node as child on child.id = ca.child_node_id
join alf_node as parent on parent.id = ca.parent_node_id
join alf_qname as q1 on q1.id = parent.type_qname_id
join alf_qname as q2 on q2.id = child.type_qname_id
join alf_node_properties as np on np.node_id = parent.id
where q1.local_name = 'authorityContainer'
and q2.local_name = 'person'
and np.qname_id = (select id from alf_qname where local_name =
'authorityDisplayName')
order by ca.qname_localname;`
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