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[英]How to use cut and paste commands as a single line command without using grep,sed awk, perl?
[英]How to use cut and awk commands to extract text input in a tabular format?
我有以下文件input.txt:
文件名:test1.v
BUG: bug 102 is fixed by some user
IO_CHANGE: there is no io_change for this version
FEATURE: no feature added
文件名:test2.v
BUG: bug 103 is fixed by some user
also bug 105 is fixed
IO_CHANGE: there is no io_change for this version
FEATURE: yes feature number 3 also feature 23
and feature 34 is added
文件名:test3.v
BUG: bug 104 is fixed by some user
FEATURE: yes feature number 2
IO_CHANGE:
我的問題:-有時BUG / FEATURE / IO_CHANGE的描述很長,每行2行,有時IO_CHANGE中沒有任何內容,因此為空白。 輸出文件應包含所有錯誤的列表,然后列出功能和io_changes。 這3種類型可以在輸入文件中以任何順序排列,我需要從文件中查找所有bug /功能/ io_changes,並逐列列出它們。
這個怎么樣。 我們將值存儲在每個文件的數組中。 在這里,我將出現在多行上的條目連接起來。
awk 'function dump() {if (vc>0)
print fn, vals["BUG"], vals["FEATURE"], vals["IO_CHANGE"]
}
BEGIN {FS=":";OFS="\t";vc=0}
FNR==1 {dump();val=""; delete vals; fn=FILENAME; vc=0}
NF>1 {val=$1; vals[val]=vals[val] $2; vc++}
NF==1 {vals[val] = vals[val] " " $1}
END{dump()}' test*v
如果找到詞組,則設置變量,如果找到其他詞組之一,則將其取消設置,然后根據文件名將行保存到數組。
刪除:之前的所有內容
然后在列中打印行
#!/bin/bash
awk 'BEGIN{printf("%-8s%-60s%-60s%-20s\n\n","FILE","|BUG","|IO","|FEATURE")}
/BUG/{a=1}/IO_CHANGE:/ || /FEATURE/{a=0} {if (a){Bug[FILENAME]=Bug[FILENAME]""$0" "}}
/IO_CHANGE:/{b=1}/BUG/ || /FEATURE/{b=0} {if (b){IO[FILENAME]=IO[FILENAME]$0" "}}
/FEATURE/{c=1}/IO_CHANGE:/ || /BUG/{c=0} {if (c){Feat[FILENAME]=Feat[FILENAME]$0" "}}
END{
for (k in Bug){
Bug[k] = substr(Bug[k],index(Bug[k],":"))
IO[k] = substr(IO[k],index(IO[k],":"))
Feat[k] = substr(Feat[k],index(Feat[k],":"))
printf("%-8s%-60s%-60s%-20s\n\n","|"k,"|"Bug[k],"|"IO[k],"|"Feat[k])}}
' test*v
不幸的是,這不會為每個文件打印多行
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