[英]How can I read this XML part?
我有一個在線XML文件的鏈接,該文件在我的應用程序中讀取。 這是XML的一部分:
<ActueleVertrekTijden>
<VertrekkendeTrein>
<RitNummer>4085</RitNummer>
<VertrekTijd>2014-06-13T22:00:00+0200</VertrekTijd>
<EindBestemming>Rotterdam Centraal</EindBestemming>
<TreinSoort>Sprinter</TreinSoort>
<RouteTekst>A'dam Sloterdijk, Amsterdam C., Duivendrecht</RouteTekst>
<Vervoerder>NS</Vervoerder>
<VertrekSpoor wijziging="false">4</VertrekSpoor>
<Opmerkingen>
<Opmerking> Rijdt vandaag niet</Opmerking>
</Opmerkingen>
</VertrekkendeTrein>
</ActueleVertrekTijden>
我想閱讀“ Opmerkingen”中列出的“ Opmerking”,它位於“ VertrekkendeTrein”中:
<Opmerkingen>
<Opmerking> Rijdt vandaag niet</Opmerking>
</Opmerkingen>
問題在於它並不總是存在的,它取決於情況。
我可以閱讀其他部分,例如“ RitNummer”和“ Vervoerder”,並使用以下代碼來做到這一點:
string urlo = "THEWEBSITE";
string resultje = HttpGeto(urlo);
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.LoadXml(resultje);
XmlNodeList nodeList = xmlDoc.SelectNodes("ActueleVertrekTijden/VertrekkendeTrein/*");
foreach (XmlNode nodelist2 in nodeList)
{//14 101517
//int i = 0;//if (i == 0) { i++; }
if (i < 1) //1
{
switch (nodelist2.Name)
{
case "VertrekTijd": string kuttijd1 = (nodelist2.InnerText);
var res1 = Regex.Match(kuttijd1, @"\d{1,2}:\d{1,2}").Value;
lblv1.Text = Convert.ToString(res1); break;
case "VertrekVertragingTekst": var tobiasisnietvantexel1 = (nodelist2.InnerText); if (tobiasisnietvantexel1 == null) {} else{ ververt1.Text = tobiasisnietvantexel1; ververt1.Visible = true; vertpic1.Visible = true; logo1.Top -= 9; lblts1.Top -= 9; } break;
case "EindBestemming": string vertrek1 = (nodelist2.InnerText); if (vertrek1 == "Uitgeest") { lblvia1.Text = "Krommenie-Ass"; } lblbs1.Text = vertrek1; break;
case "TreinSoort": lblts1.Text = (nodelist2.InnerText); break;
case "RouteTekst": lblvia1.Text = (nodelist2.InnerText); break;
case "VertrekSpoor": lbls1.Text = (nodelist2.InnerText); i++; break;
}
}
}
我做了很多嘗試:
case "Opmerking": var texeliseeneiland1
和
case "Opmerkingen/Opmerking": var texeliseeneiland1
有什么方法可以為“ Opmerking”辯護嗎?
謝謝!
最簡單但不是最優雅的解決方案是從“ Opmerkingen”節點列表中提取子節點:
case "Opmerkingen":
{
XmlNodeList nodeListOp = nodelist2.SelectNodes("Opmerking");
foreach (XmlNode node in nodeListOp)
{
if (node.Name == "Opmerking")
{
// your "Opmerking" stuff here
}
}
break;
}
您可以嘗試將XML節點列表/集合轉換為可查詢的數據結構,並使用System.Linq
來查看它是否包含和Opmerking。 盡管那是我的偏愛,因為我一直在進行很多數據庫查詢。
在您的情況下,對於switch
語句和許多情況,您可以嘗試以下操作:
對於“ Opmerkingen”,嵌套另一個案例以查看其是否具有子節點“ Opmerking”,然后對該“ Opmerking”節點進行操作。 或者讓案例“ Opmerkingen”調用一個函數以對“ opmerking”節點進行操作。
編輯一個例子:
foreach (XmlNode nodelist2 in nodeList)
{//14 101517
//int i = 0;//if (i == 0) { i++; }
if (i < 1) //1
{
switch (nodelist2.Name)
{
case "VertrekTijd": string kuttijd1 = (nodelist2.InnerText);
var res1 = Regex.Match(kuttijd1, @"\d{1,2}:\d{1,2}").Value;
lblv1.Text = Convert.ToString(res1); break;
case "VertrekVertragingTekst": var tobiasisnietvantexel1 = (nodelist2.InnerText); if (tobiasisnietvantexel1 == null) {} else{ ververt1.Text = tobiasisnietvantexel1; ververt1.Visible = true; vertpic1.Visible = true; logo1.Top -= 9; lblts1.Top -= 9; } break;
case "EindBestemming": string vertrek1 = (nodelist2.InnerText); if (vertrek1 == "Uitgeest") { lblvia1.Text = "Krommenie-Ass"; } lblbs1.Text = vertrek1; break;
case "TreinSoort": lblts1.Text = (nodelist2.InnerText); break;
case "RouteTekst": lblvia1.Text = (nodelist2.InnerText); break;
case "VertrekSpoor": lbls1.Text = (nodelist2.InnerText); i++; break;
//Here's the case you might try adding
case "Opmerkingen": var SomeVar = OpmerkingenMethod(nodelist2); break;
//or do something else that you want to do, instead of breaking,
//I do not know what you want to do with Opmerking when you get it
// so I just had the function output into another variable.
}
}
}
這是在Opmerkingen情況下可能使用的方法的示例,以便您可以使用Opmerking並執行一些操作。 再說一次,我不知道你到底想做什么
private string OpmerkingenMethod(XmlNode node)
{
//Do something with XmlNode Opmerkingen
var something = node.Name //Or whatever you want from Opmerkingen node
return something
}
這可能更多地符合您想要的內容,同樣,我還沒有測試代碼,這只是為了演示滿足您需求的代碼。
private string OpmerkingenMethod(XmlNode node)
{
//Do something with XmlNode Opmerkingen
var child = node.FistChild;
if(child.name == "Opmerking")
{
return child.InnerText // or whatever you want
}
else { return "" ; }
}
您可以在Opmerkingen的情況下調用此方法並檢查輸出,如果是您想要的,則break
switch
語句,如果不是您想要的(因為沒有opmerking或其他東西),則可以continue
進行下一種情況,或break
轉到節點列表中的下一個節點。 同樣,關鍵是在看到Opmerkingen時調用該方法,以便可以獲取Opmerkingen內部的節點或值。
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