CGIHTTPServer和Python腳本

Question

我目前正在編寫一個使用sys.stdout.print()打印HTML頁面的python程序，腳本名稱為hellocgi.py，它位於Mac OS X桌面上的cgi-bin目錄中。

這是代碼：

import sys
sys.stdout.write("Content-type: text/html \r\n\r\n")
sys.stdout.write("<!doctype html><html><head><title>Hello World</title></head>")
sys.stdout.write("<body><h2>Hello CGI</h2></body></html>")

然后，我在cgi-bin目錄中運行命令python -m CGIHTTPServer ，當我轉到url localhost:8000/hellocgi.py ，得到的是firefox中的源代碼。

如果我嘗試在cgi-bin之外運行python -m CGIHTTPServer ，則會在url localhost:8000/cgi-bin/上收到錯誤消息：

錯誤回應

錯誤代碼403。

消息：CGI腳本不是純文件（'/ cgi-bin /'）。

錯誤代碼說明：403 =禁止請求-授權將無濟於事。

在URL localhost:8000/cgi-bin/hellocgi.py firefox提示我下載源代碼。

python版本：2.7.5 Mac OS X：10.9

python -m CGIHTTPServer日志：

Serving HTTP on 0.0.0.0 port 8000 ...
127.0.0.1 - - [24/Jun/2014 18:34:49] "GET / HTTP/1.1" 200 -
127.0.0.1 - - [24/Jun/2014 18:34:51] code 403, message CGI script is not a plain file ('/cgi-bin/')
127.0.0.1 - - [24/Jun/2014 18:34:51] "GET /cgi-bin/ HTTP/1.1" 403 -
127.0.0.1 - - [24/Jun/2014 18:36:01] "GET /cgi-bin/hellocgi.py HTTP/1.1" 200 -
Traceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 253, in run_cgi
    os.execve(scriptfile, args, env)
OSError: [Errno 13] Permission denied
127.0.0.1 - - [24/Jun/2014 18:36:01] CGI script exit status 0x7f00
^CTraceback (most recent call last):
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 162, in _run_module_as_main
    "__main__", fname, loader, pkg_name)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 72, in _run_code
    exec code in run_globals
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 378, in <module>
    test()
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 374, in test
    SimpleHTTPServer.test(HandlerClass, ServerClass)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SimpleHTTPServer.py", line 216, in test
    BaseHTTPServer.test(HandlerClass, ServerClass)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 599, in test
    httpd.serve_forever()
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 236, in serve_forever
    poll_interval)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 155, in _eintr_retry
    return func(*args)

有什么幫助嗎？

Answer 1

#!/usr/bin/python
import sys
sys.stdout.write("Content-type: text/html \r\n\r\n")
sys.stdout.write("<!doctype html><html><head><title>Hello CGI</title></head>")
sys.stdout.write("<body><h2>Hello CGI</h2></body></html>")

並將premision添加到文件chmod + x querys.py中

CGIHTTPServer和Python腳本

問題描述

1 個解決方案

解決方案1
0 2015-02-11 19:51:53

CGIHTTPServer和Python腳本

問題描述

1 個解決方案

解決方案1 0 2015-02-11 19:51:53

解決方案1
0 2015-02-11 19:51:53