CGIHTTPServer and Python script
Question
I am currently writing a python program which prints HTML page using sys.stdout.print() the script name is hellocgi.py and it is inside a cgi-bin directory on the Desktop on my Mac OS X.
Here is the code:
import sys
sys.stdout.write("Content-type: text/html \r\n\r\n")
sys.stdout.write("<!doctype html><html><head><title>Hello World</title></head>")
sys.stdout.write("<body><h2>Hello CGI</h2></body></html>")
Then I am running the command python -m CGIHTTPServer inside the cgi-bin directory, and when I am going to the url localhost:8000/hellocgi.py what I get is the source code inside firefox.
If I try to run python -m CGIHTTPServer outside the cgi-bin, I get an error on url localhost:8000/cgi-bin/ :
Error response
Error code 403.
Message: CGI script is not a plain file ('/cgi-bin/').
Error code explanation: 403 = Request forbidden -- authorization will not help.
On URL localhost:8000/cgi-bin/hellocgi.py firefox prompt me to download the source code.
Python version: 2.7.5 Mac OS X: 10.9
python -m CGIHTTPServer log:
Serving HTTP on 0.0.0.0 port 8000 ...
127.0.0.1 - - [24/Jun/2014 18:34:49] "GET / HTTP/1.1" 200 -
127.0.0.1 - - [24/Jun/2014 18:34:51] code 403, message CGI script is not a plain file ('/cgi-bin/')
127.0.0.1 - - [24/Jun/2014 18:34:51] "GET /cgi-bin/ HTTP/1.1" 403 -
127.0.0.1 - - [24/Jun/2014 18:36:01] "GET /cgi-bin/hellocgi.py HTTP/1.1" 200 -
Traceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 253, in run_cgi
os.execve(scriptfile, args, env)
OSError: [Errno 13] Permission denied
127.0.0.1 - - [24/Jun/2014 18:36:01] CGI script exit status 0x7f00
^CTraceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 162, in _run_module_as_main
"__main__", fname, loader, pkg_name)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 72, in _run_code
exec code in run_globals
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 378, in <module>
test()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 374, in test
SimpleHTTPServer.test(HandlerClass, ServerClass)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SimpleHTTPServer.py", line 216, in test
BaseHTTPServer.test(HandlerClass, ServerClass)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 599, in test
httpd.serve_forever()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 236, in serve_forever
poll_interval)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 155, in _eintr_retry
return func(*args)
Any help?
1 answers
solution1
0 2015-02-11 19:51:53
#!/usr/bin/python
import sys
sys.stdout.write("Content-type: text/html \r\n\r\n")
sys.stdout.write("<!doctype html><html><head><title>Hello CGI</title></head>")
sys.stdout.write("<body><h2>Hello CGI</h2></body></html>")
and add premision to the file chmod +x querys.py
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