[英]Aggregate function in group by multiple columns
我有一個包含以下各列的表:ClientID,OrderID,ProductID,數量,每個ProductID每個OrderID僅出現一次,並且每個OrderID僅對應一個ClientID。
樣本數據:
ClientID OrderID ProductID Quantity
1 100 25 10
1 100 30 20
1 101 27 10
1 101 30 10
1 102 27 30
2 103 27 10
2 104 15 10
我需要執行以下操作:在按ClientID和ProductID分組時,我需要為其他列應用聚合函數,以便結果集包含每個ClientID最低的OrderID和每個ClientID每個ProductID的Quantity列的總和。 結果集的行數等於每個ClientID的不同ProductID的數量,並且每一行的OrderID =每個ClientID的最低OrderID,而與ProductID無關。
所需結果:
ClientID OrderID ProductID Quantity
1 100 25 10
1 100 30 30
1 100 27 40
2 103 27 10
2 103 15 10
我嘗試使用以下查詢實現此目的:
select ClientID, min(OrderID) as OrderID, ProductID, sum(Quantity) as Quantity
from table
group by ClientID, ProductID
但是由於分組的原因,結果集每個ClientID包含多個OrderID:
當前結果:
ClientID OrderID ProductID Quantity
1 100 25 10
1 100 30 30
1 101 27 40
2 103 27 10
2 104 15 10
請注意,第三和第四行的OrderID在兩個結果之間是如何不同的。
select
ClientID, MinOrderID, ProductID, SUM(quantity)
from
(
select ClientID, min(OrderID) over (partition by ClientID) as MinOrderID, ProductID, Quantity
from yourtable
) v
group by ClientID, MinOrderID, ProductID
或者
select distinct
ClientID,
min(OrderID) over (partition by ClientID),
ProductID,
sum(Quantity) over (partition by ClientID, ProductID)
from yourtable
create table dbo.aatest
(
ClientID int not null,
OrderID int not Null,
ProductID int not null,
Quantity int not null
);
insert into dbo.aatest values (1,100,25,10)
insert into dbo.aatest values (1,100,30,20)
insert into dbo.aatest values (1,101,27,10)
insert into dbo.aatest values (1,101,30,10)
insert into dbo.aatest values (1,102,27,30)
insert into dbo.aatest values (2,103,27,10)
insert into dbo.aatest values (2,104,15,10)
select * from dbo.aatest;
select
T.ClientID,
M.OrderID,
ProductID,
TotalQuantity = SUM(Quantity)
from
(select
ClientID,
OrderID = MIN(OrderID)
from
dbo.aatest
group by
ClientID) as M
join dbo.aatest as T
on M.ClientID = T.ClientID
group by
T.ClientID,
M.OrderID,
ProductID
order by
ClientID,
ProductID
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