[英]Aggregate function in group by multiple columns
我有一个包含以下各列的表:ClientID,OrderID,ProductID,数量,每个ProductID每个OrderID仅出现一次,并且每个OrderID仅对应一个ClientID。
样本数据:
ClientID OrderID ProductID Quantity
1 100 25 10
1 100 30 20
1 101 27 10
1 101 30 10
1 102 27 30
2 103 27 10
2 104 15 10
我需要执行以下操作:在按ClientID和ProductID分组时,我需要为其他列应用聚合函数,以便结果集包含每个ClientID最低的OrderID和每个ClientID每个ProductID的Quantity列的总和。 结果集的行数等于每个ClientID的不同ProductID的数量,并且每一行的OrderID =每个ClientID的最低OrderID,而与ProductID无关。
所需结果:
ClientID OrderID ProductID Quantity
1 100 25 10
1 100 30 30
1 100 27 40
2 103 27 10
2 103 15 10
我尝试使用以下查询实现此目的:
select ClientID, min(OrderID) as OrderID, ProductID, sum(Quantity) as Quantity
from table
group by ClientID, ProductID
但是由于分组的原因,结果集每个ClientID包含多个OrderID:
当前结果:
ClientID OrderID ProductID Quantity
1 100 25 10
1 100 30 30
1 101 27 40
2 103 27 10
2 104 15 10
请注意,第三和第四行的OrderID在两个结果之间是如何不同的。
select
ClientID, MinOrderID, ProductID, SUM(quantity)
from
(
select ClientID, min(OrderID) over (partition by ClientID) as MinOrderID, ProductID, Quantity
from yourtable
) v
group by ClientID, MinOrderID, ProductID
或者
select distinct
ClientID,
min(OrderID) over (partition by ClientID),
ProductID,
sum(Quantity) over (partition by ClientID, ProductID)
from yourtable
create table dbo.aatest
(
ClientID int not null,
OrderID int not Null,
ProductID int not null,
Quantity int not null
);
insert into dbo.aatest values (1,100,25,10)
insert into dbo.aatest values (1,100,30,20)
insert into dbo.aatest values (1,101,27,10)
insert into dbo.aatest values (1,101,30,10)
insert into dbo.aatest values (1,102,27,30)
insert into dbo.aatest values (2,103,27,10)
insert into dbo.aatest values (2,104,15,10)
select * from dbo.aatest;
select
T.ClientID,
M.OrderID,
ProductID,
TotalQuantity = SUM(Quantity)
from
(select
ClientID,
OrderID = MIN(OrderID)
from
dbo.aatest
group by
ClientID) as M
join dbo.aatest as T
on M.ClientID = T.ClientID
group by
T.ClientID,
M.OrderID,
ProductID
order by
ClientID,
ProductID
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