如何從包含LINQ中每個值對的列表中獲取行？

Question

我有一個具有以下結構的“夫婦”列表

public class Couple
{
    public string Code;
    public string Label;
}

還有另一個類似的“東西”列表

public class Stuff
{
    public string CodeStuff;
    public string LabelStuff;
    public int foo;
    public int bar;
    //etc...
}

我想獲取所有Stuff對象，其中List<Couple>中的每個對（代碼，標簽）與List<Stuff> （CodeStuff，Label，Stuff）匹配。

例如夫妻

Couple c = new Couple { Code = "ABC", Label = "MyLabel1" };

將僅與來自的第一行匹配

 Stuff s1 = new { CodeStuff = "ABC", LabelStuff = "MyLabel1" }; // OK
 Stuff s1 = new { CodeStuff = "ABC", LabelStuff = "MyLabel2" }; // NOT OK
 Stuff s1 = new { CodeStuff = "DEF", LabelStuff = "MyLabel1" }; // NOT OK

我嘗試使用.Where子句或.Foreach但是我不知道如何將這對夫婦（Code，Label）在一起。 你能幫助我嗎 ？

Answer 1

您需要使用linq join。

            List<Couple> lstcouple = new List<Couple>();
            List<Stuff> lstStuff = new List<Stuff>();

            var result = (from s in lstStuff
                          join c in lstcouple on new { CS = s.CodeStuff, LS = s.LabelStuff } equals new { CS = c.Code, LS = c.Label }
                          select s).ToList();

Answer 2

您嘗試過加入嗎？ 可能需要調整，但是作為一個主意：

var joined = from c in couplesList
             join s in stuffList on c.Code equals s.CodeStuff
             where c.Label == s.LabelStuff
             select s;

Answer 3

嘗試這個：

List<Stuff> stuffs = new List<Stuff>{s1,s2,s3};
List<Couple> couples = new List<Couple>{c};

var filteredList = stuffs.
                          Where
                               (x=> couples.Any(y => y.Code == x.CodeStuff)
                                 && couples.Any(y=>  y.Label == x.LabelStuff)
                               ).ToList();