[英]awk script for list comparison of number of occurrences of Key value pairs
我有2個awk語句來計算文件1和文件2中鍵的出現次數
awk '{arr[$5"."$6]++}END{for (a in arr) {print a, arr[a]}}' file1
649963661.3 1
649963658.3 1
649963660.3 1
649963655.3 1
awk '{arr[$5"."$6]++}END{for (a in arr) {print a, arr[a]}}' file2
649963658.3 1
649963660.3 2
64963661.3 1
649963655.8 1
我必須找到一個解決方案來找出file1中不存在於file2中的鍵以及file2中出現多於1次的文件1中的鍵。 另外,反之亦然
下面的代碼段在文件1中提供不同的鍵,而不是在file2中,反之亦然
awk '{print $5"\t"$6}' file1 file2 | awk '
!seen[$0]++{recs[++numRecs]=$0}
{cnt[$0]++}
END{
for (recNr=1;recNr<=numRecs;recNr++)
if (cnt[recs[recNr]] == 1)
print recs[recNr]
}'
文件內容:
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963655 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963660 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963661 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963658 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963655 8 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963660 3 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963660 3 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 64963661 3 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963658 3 Fault_reg 0
沒有測試,但這應該打印你想要的那些鍵:
awk '{k=$5"\t"$6}NR==FNR{a[k]++;next}{b[k]++}
END{for(x in b)if(b[x]==1)delete a[x];for(x in a)print x}' f1 f2
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