I have 2 awk statements to count the number of occurrences of the keys in file 1 and file 2
awk '{arr[$5"."$6]++}END{for (a in arr) {print a, arr[a]}}' file1
649963661.3 1
649963658.3 1
649963660.3 1
649963655.3 1
awk '{arr[$5"."$6]++}END{for (a in arr) {print a, arr[a]}}' file2
649963658.3 1
649963660.3 2
64963661.3 1
649963655.8 1
I have to find a solution to find out the keys present in file1 not in file2 and also the Keys in file 1 having more than 1 occurrence in file2. Also, vice versa
The below snippet provides distinct keys in file 1 not in file2 and viceversa
awk '{print $5"\t"$6}' file1 file2 | awk '
!seen[$0]++{recs[++numRecs]=$0}
{cnt[$0]++}
END{
for (recNr=1;recNr<=numRecs;recNr++)
if (cnt[recs[recNr]] == 1)
print recs[recNr]
}'
File contents:
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963655 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963660 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963661 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963658 3 Fault_reg 0 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963655 8 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963660 3 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963660 3 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 64963661 3 Fault_reg 0
Customer1 10.142.0.78 LSR001 Omnibus@147.128.231.7: 649963658 3 Fault_reg 0
didn't test, but this should print those keys you want:
awk '{k=$5"\t"$6}NR==FNR{a[k]++;next}{b[k]++}
END{for(x in b)if(b[x]==1)delete a[x];for(x in a)print x}' f1 f2
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.