[英]Mysql - WHERE a list of keys is not in subselect
我有這樣的查詢:
SELECT DISTINCT(obt.oid) AS oid, o.borrower_email
FROM `order_borrower_tracker` obt
LEFT JOIN `orders` o ON obt.oid=o.oid
WHERE obt.date_acknowledged_edelivery = 0
AND 18 NOT IN
(SELECT DISTINCT(new_status) AS new_status
FROM `order_status_history`
WHERE oid=obt.oid)
哪個有效,但現在我需要更新這個查詢,這樣不僅“18”不在subselect中,而且還有其他幾個數字....類似於
SELECT DISTINCT(obt.oid) AS oid, o.borrower_email
FROM `order_borrower_tracker` obt
LEFT JOIN `orders` o ON obt.oid=o.oid
WHERE obt.date_acknowledged_edelivery = 0
AND (18,27,29,41,53) NOT IN
(SELECT DISTINCT(new_status) AS new_status
FROM `order_status_history`
WHERE oid=obt.oid)
但顯然“(18,27,29,41,53)NOT IN”不起作用。
實現這一目標的好方法是什么? 不為每個數字鍵入AND
使用LEFT JOIN和IS NULL的技巧來查找沒有列出狀態的任何記錄的訂單:
SELECT DISTINCT(obt.oid) AS oid, o.borrower_email
FROM `order_borrower_tracker` obt
LEFT JOIN `orders` o
ON obt.oid=o.oid
LEFT JOIN `order_status_history` h
ON h.oid=obt.oid AND h.new_status IN (18,27,29,41,53)
WHERE obt.date_acknowledged_edelivery = 0
AND h.oid IS NULL
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