使用匹配的key：value對連接Python字典

Question

假設我有一個字典字典，像這樣：

{
    customers:[{customername:"Bob", age:32}],
    addresses:[{customername:"Bob", address:"123 Seseme street",addressname:"home"},
               {customername:"Bob", address:"543 42nd street", addressname:"Work"}],
    phonenumbers:[{customername:"Bob", phone:1234567, phonename:"Cell"}]
]

我想從所有其他具有key：value對'customername：“ Bob”'的字典中創建一個新字典：

Bob = {customername:"Bob", address:[{addressname:"home",address:"123 Seseme street"},
                                    {addressname:"Work", address:"543 42nd street"}],
       phone:{phonename:"Cell", phone:1234567}

第一個問題：如何以最優雅的方式創建此新詞典？

第二個問題：是否有一種方法可以將包含任意數量詞典的頂級詞典加入這些詞典，而並非所有詞典都包含該特定鍵？

Answer 1

Brionius是對的，這比起初看要容易：

l = [[x for x in db[x] if x['name']=='bob'] for x in db]
bob = [item for sublist in l for item in sublist

如果我決定保留頂級詞典，則可以這樣做：

{key:value for (key,value) in db.iteritems() for item in value if item['name']=='bob'}