[英]find values in array from another array
第一個數組是
Array
(
[2] => Course 1
[3] => C2
[4] => COMPUTATIONAL MATHEMATICS -I
[5] => BASIC ELECTRONICS
[6] => DATA STRUCTURE
[7] => COMMUNICATION SKILL
[8] => SYSTEMS PROGRAMMING
[9] => DIGITAL LOGIC
[10] => GROUP A:ENGINEERING DRAWING & WORKSHOP
)
我的第二個數組是
Array
(
[0] => Array
(
[course_id] => 2
)
[1] => Array
(
[course_id] => 4
)
[2] => Array
(
[course_id] => 6
)
[3] => Array
(
[course_id] => 10
)
)
我的預期結果是
Array
(
[2] => Course 1
[4] => COMPUTATIONAL MATHEMATICS -I
[6] => DATA STRUCTURE
[10] => GROUP A:ENGINEERING DRAWING & WORKSHOP
)
我想找出第一個數組是否包含第二個數組中的值並返回結果數組。 有什么想法嗎?
嘗試這個
$firstArray = Array();
$firstArray[2] = "Course 1";
$firstArray[3] = "C2";
$firstArray[4] = "COMPUTATIONAL MATHEMATICS -I";
$firstArray[5] = "BASIC ELECTRONICS";
$firstArray[6] = "DATA STRUCTURE";
$firstArray[7] = "COMMUNICATION SKILL";
$firstArray[8] = "SYSTEMS PROGRAMMING";
$firstArray[9] = "DIGITAL LOGIC";
$firstArray[10] = "GROUP A:ENGINEERING DRAWING & WORKSHOP";
$secondArray = Array();
$secondArray[0]["course_id"] = 2;
$secondArray[1]["course_id"] = 4;
$secondArray[2]["course_id"] = 6;
$secondArray[3]["course_id"] = 10;
$result = array();
foreach($secondArray as $second){
$result[$second["course_id"]] = $firstArray[$second["course_id"]];
}
echo '<pre>';
print_r($result);
你可以做這樣的事情。 將result
定義為數組。 並使用for循環將第二個數組的值放入其中。
$result = array();
foreach($second_array as $sa){
$result[$sa] = $first_array[$sa];
}
print_r($result);
@Ronak的答案是正確的想法...結果鍵只需要引用course_id,否則會發生未定義的偏移量錯誤。
抱歉,我會發表評論,但代表還不夠:)
$result = array();
foreach($second_array as $sa){
$result[$sa['course_id']] = $first_array[$sa['course_id']];
}
print_r($result);
您需要轉換為第二維數組,並在使用array_diff_key()之后
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