[英]How I can pass Json from Win Forms to MVC Controller
我有下面給出的MVC控制器:
public ActionResult ReceiveJson(string json)
{
//--
return Content(json, "application/json");
}
我創建了Windows窗體應用程序。 在應用程序中,我想將Json傳遞給我的MVC Controller。
我用:
string json = new JavaScriptSerializer().Serialize(myObject);
using (var client = new CookieAwareWebClient())
{
var values = new NameValueCollection
{
{ "username", login },
{ "password", haslo },
};
client.UploadValues("http://localhost/xxxxx/Login", values);
string link = "http://localhost/xxx/ReceiveJson";
client.Headers.Add("Content-Type", "application/json");
var response = client.UploadString(new Uri (link), "POST", json);
}
此代碼無效。 在ReceiveJson Controller中,我收到了null。
http://s22.postimg.org/9vxu2no9t/json.jpg
您能告訴我如何將Json從Win Forms傳遞到MVC Controller嗎?
謝謝 ;-)
這是工作代碼示例:
var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://localhost/CONTROLLER_NAME/ReceiveJson");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "GET";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
string json = new JavaScriptSerializer().Serialize(myObject);
streamWriter.Write(json);
streamWriter.Flush();
streamWriter.Close();
// If you need to read response
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
}
發送之前檢查過json值了嗎? 您是否嘗試過在不添加額外標題的情況下上傳字符串? 在您的操作中,您收到的不是字符串對象。 這是一個很好的例子。
您似乎違反了某些MVC約定。
首先,您應該將值發布在請求正文中,而不是JSON中。 看起來像這樣
using(var content = new MultipartFormDataContent()) { content.Add(new StringContent(firstPropertyName), "firstValue"); content.Add(new StringContent(secondPropertyName), "secondValue"); client.PostAsync("https://mydomain.com/xxx/ReceiveJson", content); }
其次,您應該使用[HttpPost]屬性標記您的操作
我相信這會有所幫助。
這是一個很好的工作版本:
public ActionResult NamiaryWyZapis()
{
Stream jsonDane = Request.InputStream;
jsonDane.Seek(0, System.IO.SeekOrigin.Begin);
string json = new StreamReader(jsonDane).ReadToEnd();
//--
}
解答:通過POST。
您需要將您的對象(在這種情況下為Persons)序列化為json並使用類似這種方法進行發布。 (必須同時從兩個應用程序訪問人員模型)
public async bool SendRequestAsync(string requestUrl, object data)
{
string json = JsonConvert.SerializeObject(obj, Formatting.Indented,
new JsonSerializerSettings
{
ReferenceLoopHandling = ReferenceLoopHandling.Ignore
});
try
{
HttpWebRequest request = WebRequest.Create(requestUrl) as HttpWebRequest;
if (request != null)
{
request.Accept = "application/json";
request.ContentType = "application/json";
request.Method = "POST";
using (var stream = new StreamWriter(await request.GetRequestStreamAsync()))
{
stream.Write(json);
}
using (HttpWebResponse response = await request.GetResponseAsync() as HttpWebResponse)
{
if (response != null && response.StatusCode != HttpStatusCode.OK)
throw new Exception(String.Format(
"Server error (HTTP {0}: {1}).",
response.StatusCode,
response.StatusDescription));
if (response != null)
{
Stream responseStream = response.GetResponseStream();
//return true or false depending on the ok
return GetResponseModel(responseStream);
}
}
}
}
catch (WebException ex)
{
var response = ex.Response;
Stream respStream = response.GetResponseStream();
//return true or false depending on the ok
return GetResponseModel(respStream);
}
catch (Exception e)
{
return false;
}
return false;
}
如果POST成功,則GetResponseModel方法返回要從Web讀取的模型。 然后,如果需要,可以在WinForms中注冊該成功。
控制器方法看起來像這樣
[HttpPost]
public ActionResult JsonMethod(Person p)
{
if(p != null)
return Json(true);
else return Json(false);
}
您的GetResponse的主體可能像這樣
public static T GetResponseModel<T>(Stream respStream) where T : class
{
if (respStream != null)
{
var respStreamReader = new StreamReader(respStream);
Task<string> rspObj = respStreamReader.ReadToEndAsync();
rspObj.Wait();
T jsonResponse = JsonConvert.DeserializeObject<T>(rspObj.Result);
return jsonResponse;
}
return default(T);
}
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