[英]How to validate the user input in this case?
因此,對於此程序,用戶必須輸入1到4之間的數字。當前,如果用戶錯誤輸入了其他數字,該程序將警告用戶,但問題出在字符上。 如果用戶輸入數字以外的任何類型的字符,則循環將變為無限循環。
我想知道這是否可以在C ++的入門級完成(很像當前代碼)
這是代碼
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
int firstNum,
secondNum,
subFirstNum,
subSecNum,
operNum,
num; // User's input answer for operations
bool temBool = true; // Temporary boolean used in the while loop
unsigned seed; // Random generator seed
// Use the time function to get a "seed" value for srand
seed = time(0);
srand(seed);
//Start of the loop
while (temBool)
{
//Random generated operands
firstNum = rand() % 40 + 10;
secondNum = rand() % 40 + 10;
// Set of randoms numbers for substraction where the denominator is always
// lower than the numerator.
subFirstNum = rand() % 30 + 20;
subSecNum = rand() % 10 + 10;
// Menu of Math Tutor
cout << "Math Tutor - Main Menu";
cout << endl << endl;
cout << "1. Adittion\n";
cout << "2. Subtraction\n";
cout << "3. Multiplication\n";
cout << "4. Exit Program\n";
cout << endl << endl;
cout << "Choose your operation to practice (1-4) ";
cin >> operNum;
cout << endl << endl;
// Switch for the menu's options
switch (operNum)
{
srand(seed);
case 1:
cout << "Working with addition\n";
cout << setw(3) << firstNum << "\n"
<< "+" << secondNum << "\n"
<< "---\n";
cout << "Your answer: ";
cin >> num;
if(num == firstNum + secondNum)
{
cout << "Correct answer: "
<< firstNum + secondNum << " Congratulations!\n";
}
else
{
cout << "Correct answer: "
<< firstNum + secondNum << " Sorry!\n";
}
cout << endl << endl;
break;
case 2:
cout << "Working with subtraction\n";
cout << setw(3) << subFirstNum << "\n"
<< "-" << subSecNum << "\n"
<< "---\n";
cout << "Your answer: ";
cin >> num;
if(num == subFirstNum - subSecNum)
{
cout << "Correct answer: "
<< subFirstNum - subSecNum << " Congratulations!\n";
}
else
{
cout << "Correct answer: "
<< subFirstNum + subSecNum << " Sorry!\n";
}
cout << endl << endl;
break;
case 3:
cout << "Working with multiplication\n";
cout << setw(3) << firstNum << "\n"
<< "*" << secondNum << "\n"
<< "---\n";
cout << "Your answer: ";
cin >> num;
if(num == firstNum * secondNum)
{
cout << "Correct answer: "
<< firstNum * secondNum << " Congratulations!\n";
}
else
{
cout << "Correct answer: "
<< firstNum * secondNum << " Sorry!\n";
}
cout << endl << endl;
break;
case 4:
cout << "Thank you for using Math Tutor.\n\n";
temBool = false;
break;
default:
cout << "Incorrect menu seletion. Please choose between 1 and 4.\n\n";
break;
return 0;
}
}
}
一旦流狀態由於無效的提取,格式錯誤等原因而向南移動,除了檢測到故障,確定清除故障狀態是否適用,進行故障清除並繼續操作之外,您幾乎無能為力。 有時它不適用(例如到達EOF;在那里效果不佳)。
像這樣:
#include <iostream>
#include <iomanip>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
int firstNum,
secondNum,
subFirstNum,
subSecNum,
operNum,
num; // User's input answer for operations
bool temBool = true; // Temporary boolean used in the while loop
// Use the time function to get a "seed" value for srand
std::srand(static_cast<unsigned>(std::time(nullptr)));
//Start of the loop
while (temBool)
{
//Random generated operands
firstNum = rand() % 40 + 10;
secondNum = rand() % 40 + 10;
// Set of randoms numbers for substraction where the denominator is always
// lower than the numerator.
subFirstNum = rand() % 30 + 20;
subSecNum = rand() % 10 + 10;
// Menu of Math Tutor
cout << "Math Tutor - Main Menu";
cout << endl << endl;
cout << "1. Adittion\n";
cout << "2. Subtraction\n";
cout << "3. Multiplication\n";
cout << "4. Exit Program\n";
cout << endl << endl;
cout << "Choose your operation to practice (1-4) ";
// test for successful extraction
if (!(std::cin >> operNum))
{
// yes there are times when you actually use .eof()
if (std::cin.eof())
break;
// flush out the stream through the pending newline
std::cin.clear();
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
continue;
}
cout << endl << endl;
// Switch for the menu's options
switch (operNum)
{
case 1:
cout << "Working with addition\n";
cout << setw(3) << firstNum << "\n"
<< "+" << secondNum << "\n"
<< "---\n";
cout << "Your answer: ";
cin >> num;
if(num == firstNum + secondNum)
{
cout << "Correct answer: "
<< firstNum + secondNum << " Congratulations!\n";
}
else
{
cout << "Correct answer: "
<< firstNum + secondNum << " Sorry!\n";
}
cout << endl << endl;
break;
case 2:
cout << "Working with subtraction\n";
cout << setw(3) << subFirstNum << "\n"
<< "-" << subSecNum << "\n"
<< "---\n";
cout << "Your answer: ";
cin >> num;
if(num == subFirstNum - subSecNum)
{
cout << "Correct answer: "
<< subFirstNum - subSecNum << " Congratulations!\n";
}
else
{
cout << "Correct answer: "
<< subFirstNum + subSecNum << " Sorry!\n";
}
cout << endl << endl;
break;
case 3:
cout << "Working with multiplication\n";
cout << setw(3) << firstNum << "\n"
<< "*" << secondNum << "\n"
<< "---\n";
cout << "Your answer: ";
cin >> num;
if(num == firstNum * secondNum)
{
cout << "Correct answer: "
<< firstNum * secondNum << " Congratulations!\n";
}
else
{
cout << "Correct answer: "
<< firstNum * secondNum << " Sorry!\n";
}
cout << endl << endl;
break;
case 4:
cout << "Thank you for using Math Tutor.\n\n";
temBool = false;
break;
default:
cout << "Incorrect menu seletion. Please choose between 1 and 4.\n\n";
break;
return 0;
}
}
}
用if語句包圍開關
if (operNum==1||operNum==2||operNum==3||operNum==4){
...
}
我的組織僅出於以下目的使用以下代碼。
#include <cctype>
#include <cstdlib>
#include <string>
/**
* @brief function returns the integer value of the string entered, negative
numbers in the input string are not allowed. First non-digit character
(including minus sign (-)) terminates parsing of the input string
* @exception throws no exception, return value for every input
* @param[in] input string containing the response of the user
* @return <int> errorValue = -1, non-negative value is the response of the user
*/
int menuResponse(std::string input)
{
int response = 0;
int length = 0;
response = atoi(input.c_str()); // <--- magic happens here
// check for an error in the 1st character itself, only source of false 0
// as a response value
if (isdigit(input[0]))
{
return response;
}
else
{
return -1;
}
}
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