[英]Tic-Tac-Toe Array Error
該程序是播放器和計算機之間的一個簡單的Tic Tac Toe游戲。 如果所述空間尚未被占用,則計算機僅生成一個隨機空間。 另外,我在垂直軸上有x坐標,而在水平軸上有y坐標。 我這樣做是因為我使用了二維數組,而這正是它們的結構方式。
運行該程序時,某些空格有問題,我無法找出原因。 當用戶輸入點(0,2)時,程序還將填寫點(1,0),反之亦然。 點(1,2)和(2,0)也會發生這種情況。
#include<iostream>
#include<string>
#include<stdlib.h>
#include<ctime>
using namespace std;
int board[2][2];
int chooseFirstPlayer();
void userMove(int boardArray[2][2]);
void compMove(int boardArray[2][2]);
int checkIfWinner(int boardArray[2][2]);
void displayBoard(int boardArray[2][2]);
int main(){
srand(time(NULL));
int x,y,winner;
for(x = 0; x <= 2; x++){ //sets the enitre board array to 0
for(y = 0; y <= 2; y++){
board[x][y] = 0;
}
}
if (chooseFirstPlayer() == 1){ //the user gets to movve first
do{//it will loop this until there is a winner
displayBoard(board);
userMove(board);
displayBoard(board);
winner = checkIfWinner(board);
if (winner == 0){//after the player moves, it will see if he won. If not, then the computer willbe able to move.
compMove(board);
displayBoard(board);
winner = checkIfWinner(board);
}
}while (winner == 0);//it will loop until a winner is found
}
else{//same structure as above just slightly altered to allow the computer to move first
do{
compMove(board);
displayBoard(board);
winner = checkIfWinner(board);
if (winner == 0){
userMove(board);
displayBoard(board);
winner = checkIfWinner(board);
}
}while(winner == 0);
}
if (winner = 1){
cout << "Congratulations, you won!";
}
else if (winner = 2){
cout << "Sorry, you lost!";
}
}
int chooseFirstPlayer(){//randomly genereate a number 1 or 2 to choose who moves first
return rand() % 2 + 1;
}
void userMove(int boardArray[2][2]){
int userX, userY;
do{
cout << "Enter an x coordinate: "<<endl;
cin >> userX;
cout << "Enter a y coordinate: "<<endl;
cin >> userY;
if (boardArray[userX][userY] != 0){
cout << "That loaction is already occupied"<<endl;
}
}while(boardArray[userX][userX] != 0);
boardArray[userX][userY] = 1;
}
void compMove(int boardArray[2][2]){
int compX,compY;
do{
compX = rand() % 3;
compY = rand() % 3;
}while(boardArray[compX][compY] != 0);
boardArray[compX][compY] = 2;
}
int checkIfWinner(int boardArray[2][2]){
if(boardArray[0][0] == boardArray[0][1] && boardArray[0][1] == boardArray[0][2]){ //across
return boardArray[0][0];}
else if (boardArray[1][0] == boardArray[1][1] && boardArray[1][1] == boardArray[1][2]){
return boardArray[1][0];}
else if (boardArray[2][0] == boardArray[2][1] && boardArray[2][1] == boardArray[2][2]){
return boardArray[2][0];}
else if (boardArray[0][0] == boardArray[1][0] && boardArray[1][0] == boardArray[2][0]){//down
return boardArray[0][0];}
else if (boardArray[0][1] == boardArray[1][1] && boardArray[1][1] == boardArray[2][1]){
return boardArray[0][1];}
else if (boardArray[0][2] == boardArray[1][2] && boardArray[1][2] == boardArray[2][2]){
return boardArray[0][2];}
else if (boardArray[0][0] == boardArray[1][1] && boardArray[1][1] == boardArray[2][2]){//diagonal
return boardArray[0][0];}
else if (boardArray[2][0] == boardArray[1][1] && boardArray[1][1] == boardArray[0][2]){
return boardArray[2][0];}
else{
return 0;
}
}
void displayBoard(int boardArray[2][2]){
system("CLS");
cout <<" "<<" Y1 "<<" Y2 "<<" Y3 "<<endl;
cout <<" X1 "<< "__"<<boardArray[0][0]<<"__|__"<<boardArray[0][1]<<"__|__"<<boardArray[0][2]<<"__"<<endl;
cout <<" X2 "<< "__"<<boardArray[1][0]<<"__|__"<<boardArray[1][1]<<"__|__"<<boardArray[1][2]<<"__"<<endl;
cout <<" X3 "<< " "<<boardArray[2][0]<<" | "<<boardArray[2][1]<<" | "<<boardArray[2][2]<<" "<<endl;
}
我的IDE是Dev-C ++(5.4.2)
您的數組是2x2,您可以執行以下操作:
for(x = 0; x <= 2; x++){ //sets the enitre board array to 0
for(y = 0; y <= 2; y++){
board[x][y] = 0;
}
}
而您不應該訪問內存。 這意味着您將越界!
x
和y
最終將取等於2的值。
數組的索引從0開始直到其大小-1。
因此,您可以使用3x3的數組,或更改代碼(以及直到2的checkIfWinner
函數)。
邊注:
您在這里錯過了相等運算符:
if (winner = 1){
cout << "Congratulations, you won!";
}
else if (winner = 2){
cout << "Sorry, you lost!";
}
如果保持原樣會怎樣? 賦值將發生並導致邏輯為真,因此第一個條件將始終為真(第二個條件為零,但代碼不會走得那么遠)。
因此,用==
更改=
。
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