無法將嵌套對象保存在實體框架中

Question

我是Asp.Net MVC的新手。 我在我的項目中使用了標准會員資格提供程序。 我有應用程序用戶和ApplicationDbContext

  public class ApplicationUser : IdentityUser
    {
    [Required]
        public virtual UserInfo UserInfo { get; set; }
        public virtual ICollection<Lot> Lots { get; set; }
    }

    public class ApplicationDbContext : IdentityDbContext<ApplicationUser>
    {
        public DbSet<Lot> Lots { get; set; }
        public DbSet<Product> Products { get; set; }

        public DbSet<UserInfo> UserInfoes { get; set; }

        public DbSet<PersonalInformation> PersonalInformations { get; set; } 
        public ApplicationDbContext()
            : base("DefaultConnection")
        {
        }
    }

和UserInfo

public class UserInfo
    {
        [Key]
        public int UserInfoId { get; set; }
        public DateTime RegistarationDate { get; set; }
        public decimal Money { get; set; }
        public decimal CurrentDebt { get; set; }
        public virtual PersonalInformation PersonalInformation { get; set; }
        public virtual ApplicationUser ApplicationUser { get; set; }
    }

個人信息

 public class PersonalInformation
    {
        public int PersonalInformationId { get; set; }
        public string FirstName { get; set; }
        public string LastName { get; set; }
        public string Telephone { get; set; }
        public Adress Adress { get; set; }
    }

我的RegisterViewModel

public class RegisterViewModel
    {
        [Required]
        [Display(Name = "User name")]
        public string UserName { get; set; }

        [Required]
        [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 6)]
        [DataType(DataType.Password)]
        [Display(Name = "Password")]
        public string Password { get; set; }

        [DataType(DataType.Password)]
        [Display(Name = "Confirm password")]
        [Compare("Password", ErrorMessage = "The password and confirmation password do not match.")]
        public string ConfirmPassword { get; set; }

        public string FirstName { get; set; }
        public string LastName { get; set; }
        public decimal Money { get; set; }

        public string Telephone { get; set; }
    }

和動作在控制器中創建

 [HttpPost]
        [AllowAnonymous]
        [ValidateAntiForgeryToken]
        public async Task<ActionResult> Register(RegisterViewModel model)
        {
            if (ModelState.IsValid)
            {
                var user = new ApplicationUser()
                {
                    UserName = model.UserName,
                    UserInfo = new UserInfo()
                    {
                        CurrentDebt = 0,
                        Money = model.Money,
                        RegistarationDate = DateTime.Now,
                        PersonalInformation = new PersonalInformation()
                        {
                            FirstName = model.FirstName,
                            LastName = model.LastName,
                            Telephone = model.Telephone,
                        }
                    }
                };
                var result = await UserManager.CreateAsync(user, model.Password);
                if (result.Succeeded)
                {
                    await SignInAsync(user, isPersistent: false);
                    return RedirectToAction("Index", "Home");
                }
                else
                {
                    AddErrors(result);
                }
            }

            // If we got this far, something failed, redisplay form
            return View(model);
        }

當我填寫行動中提到的所有字段時，我收到此錯誤

無法將值NULL插入表'DefaultConnection.dbo.UserInfoes'的'UserInfoId'列中； 列不允許為空。 INSERT失敗。 該語句已終止。

有人可以幫我嗎？ 非常感謝

Answer 1

您需要告訴EF UserInfoId是針對該表的Key ，因此它將其映射為Identity 。

這樣的事情將在映射文件中起作用：

public class UserInfoMap : EntityTypeConfiguration<UserInfo>
{
    public UserInfoMap()
    {
        ToTable("UserInfo");
        HasKey(m => m.UserInfoId );
    }
}

當代碼首次遷移運行時，它會生成如下內容：

CreateTable(
    "dbo.UserInfo",
    c => new
        {
            UserInfoId = c.Int(nullable: false, identity: true)
)

這意味着您無需指定ID，因為它會自動填充到數據庫中。