[英]Unhandled exception at 0x76fe15de in GLut.h/ osfinfo.c/ dbgheap.c/ mlock.c
[英]dbgheap.c throws access violation exception
我開發了下面的代碼,效果很好:
#include "header.h"
int test_DGGEV_11_14a(){
const int n=3;
double a[n][n]={1,1,1,2,3,4,3,5,2};
double b[n][n]={-10,-3,12,14,14,12,16,16,18};
//double a[n][n]={1,7,3,2,9,12,5,22,7};
//double b[n][n]={1,7,3,2,9,12,5,22,7};
/*const int n=2;
double a[n][n]={1e-16,0,0,1e-15};
double b[n][n]={1e-16,0,0,1e-15};*/
lapack_int info;
double alphar[n]={0.0};
double alphai[n]={0.0};
double beta[n]={0.0};
double vl[n][n]={0.0};
double vr[n][n]={0.0};
info=LAPACKE_dggev(LAPACK_ROW_MAJOR,'V','V',n,*a,n,*b,n,alphar,alphai,beta,*vl,n,*vr,n);
std::cout<<"right eigen vector (what we want):\n";
for(int i=int(0);i<n;i++){
for(int j=int(0);j<n;j++){
printf("%1f ",vr[i][j]);
}
printf("\n");
}
std::cout<<"left eigen vector:\n";
for(int i=int(0);i<n;i++){
for(int j=int(0);j<n;j++){
printf("%1f ",vl[i][j]);
}
printf("\n");
}
std::cout<<"eigen values:\n";
for(int i=int(0);i<n;i++){
if(beta[i]>DBL_MIN || beta[i]<-DBL_MIN){
printf("%1f ",alphar[i]/beta[i]);
printf("\n");
}else{
printf("%1f ","beta is zero");
printf("\n");
}
}
return info;
}
我修改了上面的正確代碼,以對大型矩陣使用LAPACKE DGGEV例程,修改后的代碼如下所示:
#include "header.h"
int test_DGGEV_11_17a(){
const int r=342;
const int c=342;
double**a=NULL;//stiffness
a=new double *[r];
for(int i=int(0);i<r;i++)
a[i]=new double[c];
readFile("Input_Files/OUTPUT_sub_2_stiffness.txt",a,r,c);
writeFile("Output_Files/K.txt",a,r,c);//to check if readFile was OK
double**b=NULL;//mass
b=new double*[r];
for(int i=int(0);i<r;i++)
b[i]=new double[c];
readFile("Input_Files/OUTPUT_sub_2_mass.txt",b,r,c);
writeFile("Output_Files/M.txt",b,r,c);//to check if readFile was OK
const int n=r;//r=c=n
lapack_int info=110;
double alphar[n]={0.0};
double alphai[n]={0.0};
double beta[n]={0.0};
//double vl[n][n]={0.0};//generates stack overflow
double**vl=NULL;
vl=new double*[r];
for(int i=int(0);i<r;i++)
vl[i]=new double[c];
for(int i=int(0);i<r;i++)
for(int j=int(0);j<c;j++)
vl[i][j]=0.0;
//double vr[n][n]={0.0};//generates stack overflow
double**vr=NULL;
vr=new double*[r];
for(int i=int(0);i<r;i++)
vr[i]=new double[c];
for(int i=int(0);i<r;i++)
for(int j=int(0);j<c;j++)
vr[i][j]=0.0;
info=LAPACKE_dggev(LAPACK_ROW_MAJOR,'V','V',n,*a,n,*b,n,alphar,alphai,beta,*vl,n,*vr,n);
return info;
}
在上面修改的代碼中(對於大型矩陣),我必須從堆中分配內存,因為否則,堆棧將溢出。 問題是,當我通過new
從堆中分配內存時,出現以下與堆相關的異常,該異常發生在dbgheap.c
(調試CRT堆功能)內部:
有人知道為什么會發生這種異常嗎? 也許這與LAPACKE DLL使用不同的堆進行分配這一事實有關...我不知道。
編輯:
堆棧跟蹤是這樣的:
編輯:
最終通過用1D數組替換所有2D數組解決了該問題。 以下代碼是正確的代碼,可以正常工作。 有關此解決方案的詳細信息,請參見“ Ilya Kobelevskiy”的答案。
int test_DGGEV_11_18a(){
const int r=342;
const int c=342;
double*a=NULL;//stiffness
a=new double [r*c];
for(int i=int(0);i<r*c;i++)
a[i]=0.0;
readFile_1Darray("Input_Files/OUTPUT_sub_2_stiffness.txt",a,r,c);
writeFile_1Darray("Output_Files/K.txt",a,r,c);//to check if readFile was OK
double*b=NULL;//mass
b=new double[r*c];
for(int i=int(0);i<r*c;i++)
b[i]=0.0;
readFile_1Darray("Input_Files/OUTPUT_sub_2_mass.txt",b,r,c);
writeFile_1Darray("Output_Files/M.txt",b,r,c);//to check if readFile was OK
const int n=r;//r=c=n
lapack_int info=110;
//double alphar[n]={0.0};
double*alphar=NULL;
alphar=new double[n];
for(int i=int(0);i<n;i++)
alphar[i]=0.0;
//double alphai[n]={0.0};
double*alphai=NULL;
alphai=new double[n];
for(int i=int(0);i<n;i++)
alphai[i]=0.0;
//double beta[n]={0.0};
double*beta=NULL;
beta=new double[n];
for(int i=int(0);i++;)
beta[i]=0.0;
//double vl[n][n]={0.0};//generates stack overflow
double*vl=NULL;
vl=new double[r*c];
for(int i=int(0);i<r*c;i++)
vl[i]=0.0;
//double vr[n][n]={0.0};//generates stack overflow
double*vr=NULL;
vr=new double[r*c];
for(int i=int(0);i<r*c;i++)
vr[i]=0.0;
info=LAPACKE_dggev(LAPACK_ROW_MAJOR,'V','V',n,a,n,b,n,alphar,alphai,beta,vl,n,vr,n);
std::cout<<"info returned by LAPACKE_dggev:\t"<<info<<'\n';
double*eigValueReal=NULL;
eigValueReal=new double[n];
for(int i=int(0);i<n;i++)
eigValueReal[i]=0.0;
for(int i=int(0);i<n;i++)
eigValueReal[i]=alphar[i]/beta[i];
write1Darray("Output_Files/eigValueReal_LAPACKE_DGGEV.txt",eigValueReal,n);
write1Darray("Output_Files/beta.txt",beta,n);
writeFile_1Darray("Output_Files/eigVectorRight_LAPACKE_DGGEV.txt",vr,r,c);
delete[] a;
delete[] b;
delete[] alphar;
delete[] alphai;
delete[] beta;
delete[] vl;
delete[] vr;
delete[] eigValueReal;
return info;
}
根據文檔, LAPACKE_dggev希望將double *作為輸入,因此所有矩陣都需要存儲為線性數組。
代替
double**a=NULL;//stiffness
a=new double *[r];
for(int i=int(0);i<r;i++)
a[i]=new double[c];
你應該用
double*a=new double[c*r];//stiffness
所有矩陣的變化都相似。 矩陣元素可以作為a [i,j]的a [i * c + j]訪問。 現在,您的代碼可能還有其他問題,但這是一個顯而易見的問題,可能會導致您看到錯誤。
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