RestSharp反序列化不起作用

Question

下面的原始輸出（從RestResponse.Content屬性獲得）沒有被反序列化。 是否因為“ ns1”被添加為前綴？ 我做錯什么了嗎？

這是撥打電話時返回的原始JSON內容：

{“ ns1.model-response-list”：{“ @ throttle”：“ 2”，“ @ total-models”：“ 3372”，“ ns1.model-re sponses”：{“ ns1.model”：[{ “ @mh”：“ 0x20e800”，“ ns1.attribute”：{“ @ id”：“ 0x1006e”，“ $”：“ S servername.com”}}，{“ @ mh”：“ 0x21a400”，“ ns1 .attribute“：{” @ id“：” 0x100 6e“，” $“：” servername.com“}}}}，” ns1.link“：{” @ rel“：” next“，” @ href“： “ http：// ipaddress / spectrum / restful / devices？id = 93fc1a07-60be-4dd5-964c-7 e8660dd3028＆start = 2＆throttlesize = 2”，“ @ type”：“ application / xml”}}}

class Program
{
static void Main(string[] args)
{
var client = new RestClient(Spectrum.Endpoints.Development);
client.Authenticator = new HttpBasicAuthenticator("myid", "mypassword");

var request = new RestRequest(Method.GET);
request.RequestFormat = DataFormat.Xml;
request.Resource = "devices?{attr}&{throttlesize}";
request.AddParameter("attr", Spectrum.Attributes.ModelName);
request.AddParameter("throttlesize", "2");

IRestResponse<ModelResponseList> response = client.Execute<ModelResponseList>(request);

Console.Write(response.Data.Throttle); // This line keeps returning 0, but should return 2
}

以下是應保存數據的類：

[DeserializeAs(Name = "model-response-list")]
public class ModelResponseList
{
    [DeserializeAs(Name = "throttle")]
    public int Throttle { get; set; }

    [DeserializeAs(Name = "total-models")]
    public int TotalModels { get; set; }

    [DeserializeAs(Name = "model-responses")]
    public List<Model> ModelResponses { get; set; }

    [DeserializeAs(Name = "link")]
    public Link Link { get; set; }
}

public class Model
{
    public string Mh { get; set; }
    public ModelAttribute Attribute { get; set; }
}

public class ModelAttribute
{
    public string Id { get; set; }
    public string Value { get; set; }
}

public class Link
{
    public string Rel { get; set; }
    // Note! Href must be escaped, e.g. "&" => "&amp;" or comment this prop out
    public string Href { get; set; }
    public string Type { get; set; }
}

Answer 1

我真的不知道為什么要向您提供這個答案。 但是我還是。 您應該通過NuGet來獲取Json.NET，並讓它幫助您。 它比RestSharp的內置反序列化功能更復雜。

一旦有了Json.NET，就可以使用下面的類對JSON進行反序列化。 這次，我希望您在收到答案后不會刪除問題，而是接受並可能對其進行投票？

因此，使用

var response = client.Execute(request);
var deserialized = JsonConvert.DeserializeObject<Wrapper>(response.Content);
Console.WriteLine(JsonConvert.SerializeObject(deserialized));

輸出到控制台以下

{ “ns1.model響應列表”：{ “@油門”：2 “@總的模型”：3372， “ns1.model - 響應”：{ “ns1.model”：[{ “@ MH”： “0x20e800”， “ns1.attribute”：{ “@ ID”： “0x1006e”， “$”： “Sservername.com”}}，{ “@ MH”： “0x21a400”， “ns1.attribute”：{” @id“：” 0x1006e“，” $“：” servername.com“}}]}，” ns1.link“：{” @ rel“：” next“，” @ href“：” hxxp：// ipaddress / Spectrum / restful / devices？id = 93fc1a07-60be-4dd5-964c-7 e8660dd3028＆start = 2＆throttlesize = 2“，” @ type“：” application / xml“}}}

如果您使用下面的類

[JsonObject]
public class Wrapper
{
    [JsonProperty(PropertyName = "ns1.model-response-list")]
    public ModelResponseList ModelResponseList { get; set; }
}

[JsonObject]
public class ModelResponseList
{
    [JsonProperty(PropertyName = "@throttle")]
    public int Throttle { get; set; }

    [JsonProperty(PropertyName = "@total-models")]
    public int TotalModels { get; set; }

    [JsonProperty(PropertyName = "ns1.model-responses")]
    public Responses ModelResponses { get; set; }

    [JsonProperty(PropertyName = "ns1.link")]
    public Link Link { get; set; }
}

[JsonObject]
public class Responses
{
    [JsonProperty(PropertyName = "ns1.model")]
    public List<Model> Model { get; set; }
}

[JsonObject]
public class Model
{
    [JsonProperty(PropertyName = "@mh")]
    public object Mh { get; set; }

    [JsonProperty(PropertyName = "ns1.attribute")]
    public ModelAttribute Attribute { get; set; }
}

[JsonObject]
public class ModelAttribute
{
    [JsonProperty(PropertyName = "@id")]
    public string Id { get; set; }

    [JsonProperty(PropertyName = "$")]
    public string Value { get; set; }
}

[JsonObject]
public class Link
{
    [JsonProperty(PropertyName = "@rel")]
    public string Rel { get; set; }

    [JsonProperty(PropertyName = "@href")]
    public string Href { get; set; }

    [JsonProperty(PropertyName = "@type")]
    public string Type { get; set; }
}