[英]java - Exception in thread “main” java.lang.NumberFormatException: For input string: “” at
[英]Exception in thread “main” java.lang.NumberFormatException: For input string: “” Array
我在程序中找不到任何問題。 每次用戶輸入一個數字時,我都希望將其保存在數組A中,但是當用戶嘗試鍵入第二個數字時,將出現NumberFormatException
錯誤。
Exception in thread "main" java.lang.NumberFormatException: For input string: ""
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
at java.lang.Integer.parseInt(Integer.java:470)
at java.lang.Integer.parseInt(Integer.java:499)
at practice.test(end.java:22)
at end.main(end.java:7)
這是程序:
import java.io.*;
class end {
public static void main(String[] args) throws IOException {
practice obj = new practice();
obj.test();
}
}
class practice {
void test() throws IOException {
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(isr);
int A[] = new int[5];
String x;
int a, b, c, i = 0;
for(i = 0; i < 5; i++) {
System.out.println("Insert a number");
x = br.readLine();
A[i] = Integer.parseInt(x);
}
}
}
只要輸入數字,代碼就可以正常工作。 如果輸入空字符串,它將給您錯誤已發布的內容。
可能需要add a check for empty string
。
if(!x.isEmpty()){
A[i] = Integer.parseInt(x);
}
public class end {
public static void main(String[] args) throws IOException {
practice obj = new practice();
obj.test();
}
}
class practice {
void test() throws IOException {
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(isr);
int A[] = new int[5];
String x;
int a, b, c, i = 0;
for (i = 0 ; i < 5 ; i++) {
System.out.println("Insert a number");
x = br.readLine();
A[i] = Integer.parseInt(x);
}
for (i = 0 ; i < 5 ; i++) {
System.out.println(A[i]);
}
}
}
輸出量
Insert a number
2
Insert a number
3
Insert a number
4
Insert a number
5
Insert a number
6
User input
2
3
4
5
6
看來您嘗試從Stacktrace輸入一個空字符串,應該檢查輸入是否為空...
InputStreamReader isr = new InputStreamReader(System.in);
BufferedReader br = new BufferedReader(isr);
int A[] = new int[5];
String x;
int a, b, c, i = 0;
for(i = 0; i < 5; i++) {
System.out.println("Insert a number");
x = br.readLine();
//check if input is empty
if(!x.isEmpty()){
A[i] = Integer.parseInt(x);
}
}
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