在列表Python中添加元素

Question

under__list =[[74, 0.1423287845938018, None, None, 10, 
   1.9099604642265018, 0.5185563065935468, 1.6825659992347914, 
   3.547506695574544, 2.7789822726693023, 20051, 0, 25, None, ' >50K'],
  [44, 0.9181229773462783, None, None, 14, 0.17973300970873787, 
   0.1644822006472492, 0.13940129449838187, 1.1252427184466018, 
   0.4357200647249191, 0, 0, 40, None, ' <=50K']]

我有上面的列表，但我想將元素添加到一起但跳過None和">=50"元素。

即使我不知道None數值的位置，我希望能夠做到這一點。 有什么建議？

for item in zip(under__list[row]):
    under__list.append(int(sum(item[0])))

尋找以下輸出：

[1182, 25.2452245, None, None, 9212, 256, 2624, 25.24,
   2532, 25, 2005252, 52, 25632, None, ' >50K']

這將是一個添加了數字的列表。

Answer 1

看起來你想要對所有內部列表中相同索引的項進行求和。 首先，你需要使用帶* zip ，然后在列表中理解每行的第一項是一個Number類型的實例，或者只是int或float （ isinstance(x[0], (int, float)) ），如果是，則將其他用作第一項作為值。

>>> from numbers import Number
>>> [sum(x) if isinstance(x[0], Number) else x[0] for x in zip(*under__list)]
[118, 1.0604517619400802, None, None, 24, 2.0896934739352395, 0.683038507240796, 1.8219672937331732, 4.672749414021146, 3.2147023373942214, 20051, 0, 65, None, ' >50K']

表達式sum(x) if isinstance(x[0], Number) else x[0]稱為條件表達式 。

Answer 2

for item in under_list:
    item_ = filter(lambda x: x != None and x >= 50, under_list)
    # Here compute sum of item_ and append to the right place

Answer 3

寫一個函數來返回你需要的東西：

def foo(thing):
    try:
        return sum(thing)
    except TypeError:
        return thing[0]

將函數map到under__list的zip ped 行

>>> under__list =[[74, 0.1423287845938018, None, None, 10, 1.9099604642265018, 0.5185563065935468, 1.6825659992347914, 3.547506695574544, 2.7789822726693023, 20051, 0, 25, None,' >50K'], [44, 0.9181229773462783, None, None, 14, 0.17973300970873787, 0.1644822006472492, 0.13940129449838187, 1.1252427184466018, 0.4357200647249191, 0, 0, 40, None, ' <=50K']]

>>> map(foo, zip(*under__list))
[118, 1.0604517619400802, None, None, 24, 2.0896934739352395, 0.683038507240796, 1.8219672937331732, 4.672749414021146, 3.2147023373942214, 20051, 0, 65, None, ' >50K']
>>>